HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
Unicode version

Theorem a4imt 1160
Description: Closed theorem form of a4im 1161.
Assertion
Ref Expression
a4imt |- (A.x((ps -> A.xps) /\ (x = y -> (ph -> ps))) -> (A.xph -> ps))

Proof of Theorem a4imt
StepHypRef Expression
1 imim2 14 . . . . . 6 |- ((ps -> A.xps) -> ((ph -> ps) -> (ph -> A.xps)))
21imim2d 25 . . . . 5 |- ((ps -> A.xps) -> ((x = y -> (ph -> ps)) -> (x = y -> (ph -> A.xps))))
32imp 350 . . . 4 |- (((ps -> A.xps) /\ (x = y -> (ph -> ps))) -> (x = y -> (ph -> A.xps)))
43com23 32 . . 3 |- (((ps -> A.xps) /\ (x = y -> (ph -> ps))) -> (ph -> (x = y -> A.xps)))
5419.20ii 997 . 2 |- (A.x((ps -> A.xps) /\ (x = y -> (ph -> ps))) -> (A.xph -> A.x(x = y -> A.xps)))
6 ax-9o 1125 . 2 |- (A.x(x = y -> A.xps) -> ps)
75, 6syl6 22 1 |- (A.x((ps -> A.xps) /\ (x = y -> (ph -> ps))) -> (A.xph -> ps))
Colors of variables: wff set class
Syntax hints:   -> wi 3   /\ wa 223  A.wal 956   = wceq 958
This theorem is referenced by:  a12lem1 1378
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 965  ax-4 975  ax-5o 977  ax-9o 1125
This theorem depends on definitions:  df-bi 147  df-an 225
Copyright terms: Public domain