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Theorem cdeqi 3090
Description: Deduce conditional equality. (Contributed by Mario Carneiro, 11-Aug-2016.)
Hypothesis
Ref Expression
cdeqi.1  |-  ( x  =  y  ->  ph )
Assertion
Ref Expression
cdeqi  |- CondEq ( x  =  y  ->  ph )

Proof of Theorem cdeqi
StepHypRef Expression
1 cdeqi.1 . 2  |-  ( x  =  y  ->  ph )
2 df-cdeq 3089 . 2  |-  (CondEq (
x  =  y  ->  ph )  <->  ( x  =  y  ->  ph ) )
31, 2mpbir 201 1  |- CondEq ( x  =  y  ->  ph )
Colors of variables: wff set class
Syntax hints:    -> wi 4  CondEqwcdeq 3088
This theorem is referenced by:  cdeqth  3092  cdeqnot  3093  cdeqal  3094  cdeqab  3095  cdeqim  3098  cdeqcv  3099  cdeqeq  3100  cdeqel  3101
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-3 7  ax-mp 8
This theorem depends on definitions:  df-bi 178  df-cdeq 3089
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