Theorem eqimss2 2113

Description: Equality implies the subclass relation.

Assertion

Ref	Expression
eqimss2	|- (B = A -> A (_ B)

Proof of Theorem eqimss2

Step	Hyp	Ref	Expression
1		eqimss 2112	. 2 |- (A = B -> A (_ B)
2	1	eqcoms 1481	1 |- (B = A -> A (_ B)

Syntax hints:   -> wi 3   = wceq 958   (_ wss 2050

This theorem is referenced by:  vss 2311  suc11 3099  dmcoeq 3372  xp11 3482  fconst3 3856  oaass 4201  odi 4216  oen0 4219  zorn 4807  subgres 8113  hstoht 10154  dmdi2 10226

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-10 968  ax-12 970  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-16 1212  ax-11o 1220  ax-ext 1462

This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 983  df-sb 1174  df-clab 1467  df-cleq 1472  df-clel 1475  df-in 2054  df-ss 2056

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