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Theorem equid1 2097
 Description: Identity law for equality (reflexivity). Lemma 6 of [Tarski] p. 68. This is often an axiom of equality in textbook systems, but we don't need it as an axiom since it can be proved from our other axioms (although the proof, as you can see below, is not as obvious as you might think). This proof uses only axioms without distinct variable conditions and thus requires no dummy variables. A simpler proof, similar to Tarki's, is possible if we make use of ax-17 1603; see the proof of equid 1644. See equid1ALT 2115 for an alternate proof. (Contributed by NM, 5-Aug-1993.) (Proof modification is discouraged.) (New usage is discouraged.)
Assertion
Ref Expression
equid1

Proof of Theorem equid1
StepHypRef Expression
1 ax-5o 2075 . . . 4
2 ax-4 2074 . . . . 5
3 ax-12o 2081 . . . . 5
42, 2, 3sylc 56 . . . 4
51, 4mpg 1535 . . 3
6 ax-9o 2077 . . 3
75, 6syl 15 . 2
8 ax-6o 2076 . 2
97, 8pm2.61i 156 1
 Colors of variables: wff set class Syntax hints:   wn 3   wi 4  wal 1527 This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-3 7  ax-mp 8  ax-gen 1533  ax-4 2074  ax-5o 2075  ax-6o 2076  ax-9o 2077  ax-12o 2081
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