Theorem equtr 1127

Description: A transitive law for equality.

Assertion

Ref	Expression
equtr	|- (x = y -> (y = z -> x = z))

Proof of Theorem equtr

Step	Hyp	Ref	Expression
1		ax-8 961	. 2 |- (y = x -> (y = z -> x = z))
2	1	equcoms 1126	1 |- (x = y -> (y = z -> x = z))

Syntax hints:   -> wi 3   = wceq 953

This theorem is referenced by:  equtrr 1128  equtr2 1129  equequ1 1130  equvin 1270  a12lem1 1369  axsep 2692  dscmet 7856

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 960  ax-8 961  ax-12 965  ax-4 970  ax-5o 972  ax-6o 975  ax-9o 1119

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