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Theorem excxor 1318
Description: This tautology shows that xor is really exclusive. (Contributed by FL, 22-Nov-2010.)
Assertion
Ref Expression
excxor  |-  ( (
ph  \/_  ps )  <->  ( ( ph  /\  -.  ps )  \/  ( -.  ph  /\  ps )
) )

Proof of Theorem excxor
StepHypRef Expression
1 df-xor 1314 . 2  |-  ( (
ph  \/_  ps )  <->  -.  ( ph  <->  ps )
)
2 xor 862 . 2  |-  ( -.  ( ph  <->  ps )  <->  ( ( ph  /\  -.  ps )  \/  ( ps  /\  -.  ph )
) )
3 ancom 438 . . 3  |-  ( ( ps  /\  -.  ph ) 
<->  ( -.  ph  /\  ps ) )
43orbi2i 506 . 2  |-  ( ( ( ph  /\  -.  ps )  \/  ( ps  /\  -.  ph )
)  <->  ( ( ph  /\ 
-.  ps )  \/  ( -.  ph  /\  ps )
) )
51, 2, 43bitri 263 1  |-  ( (
ph  \/_  ps )  <->  ( ( ph  /\  -.  ps )  \/  ( -.  ph  /\  ps )
) )
Colors of variables: wff set class
Syntax hints:   -. wn 3    <-> wb 177    \/ wo 358    /\ wa 359    \/_ wxo 1313
This theorem is referenced by:  f1omvdco2  27368  psgnunilem5  27394
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-3 7  ax-mp 8
This theorem depends on definitions:  df-bi 178  df-or 360  df-an 361  df-xor 1314
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