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Theorem jaob 424
Description: Disjunction of antecedents. Compare Theorem *4.77 of [WhiteheadRussell] p. 121.
Assertion
Ref Expression
jaob |- (((ph \/ ch) -> ps) <-> ((ph -> ps) /\ (ch -> ps)))

Proof of Theorem jaob
StepHypRef Expression
1 orc 269 . . . 4 |- (ph -> (ph \/ ch))
21imim1i 16 . . 3 |- (((ph \/ ch) -> ps) -> (ph -> ps))
3 olc 268 . . . 4 |- (ch -> (ph \/ ch))
43imim1i 16 . . 3 |- (((ph \/ ch) -> ps) -> (ch -> ps))
52, 4jca 288 . 2 |- (((ph \/ ch) -> ps) -> ((ph -> ps) /\ (ch -> ps)))
6 jao 340 . . 3 |- ((ph -> ps) -> ((ch -> ps) -> ((ph \/ ch) -> ps)))
76imp 350 . 2 |- (((ph -> ps) /\ (ch -> ps)) -> ((ph \/ ch) -> ps))
85, 7impbi 157 1 |- (((ph \/ ch) -> ps) <-> ((ph -> ps) /\ (ch -> ps)))
Colors of variables: wff set class
Syntax hints:   -> wi 3   <-> wb 146   \/ wo 222   /\ wa 223
This theorem is referenced by:  pm4.77 425  pm3.44 432  pm5.53 485  pm4.83 742  unss 2207  ralpr 2432  prsspw 2484  intun 2566  intpr 2567  ordsseleq 2982  relop 3281  cau2 6913  caubnd 6926  spwpr2 8654
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225
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