Theorem olcs 275

Description: Deduction eliminating disjunct.

Hypothesis

Ref	Expression
olcs.1	|- ((ph \/ ps) -> ch)

Assertion

Ref	Expression
olcs	|- (ps -> ch)

Proof of Theorem olcs

Step	Hyp	Ref	Expression
1		olc 268	. 2 |- (ps -> (ph \/ ps))
2		olcs.1	. 2 |- ((ph \/ ps) -> ch)
3	1, 2	syl 10	1 |- (ps -> ch)

Syntax hints:   -> wi 3   \/ wo 222

This theorem is referenced by:  eueq3 1915  sucid 3046  0nn0 6068  bcpasc 6915

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7

This theorem depends on definitions:  df-bi 147  df-or 224

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