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Theorem or12 258
Description: A rearrangement of disjuncts.
Assertion
Ref Expression
or12 |- ((ph \/ (ps \/ ch)) <-> (ps \/ (ph \/ ch)))

Proof of Theorem or12
StepHypRef Expression
1 bi2.04 160 . . 3 |- ((-. ps -> (-. ph -> ch)) <-> (-. ph -> (-. ps -> ch)))
2 df-or 224 . . . 4 |- ((ph \/ ch) <-> (-. ph -> ch))
32imbi2i 185 . . 3 |- ((-. ps -> (ph \/ ch)) <-> (-. ps -> (-. ph -> ch)))
4 df-or 224 . . . 4 |- ((ps \/ ch) <-> (-. ps -> ch))
54imbi2i 185 . . 3 |- ((-. ph -> (ps \/ ch)) <-> (-. ph -> (-. ps -> ch)))
61, 3, 53bitr4r 184 . 2 |- ((-. ph -> (ps \/ ch)) <-> (-. ps -> (ph \/ ch)))
7 df-or 224 . 2 |- ((ph \/ (ps \/ ch)) <-> (-. ph -> (ps \/ ch)))
8 df-or 224 . 2 |- ((ps \/ (ph \/ ch)) <-> (-. ps -> (ph \/ ch)))
96, 7, 83bitr4 183 1 |- ((ph \/ (ps \/ ch)) <-> (ps \/ (ph \/ ch)))
Colors of variables: wff set class
Syntax hints:  -. wn 2   -> wi 3   <-> wb 146   \/ wo 222
This theorem is referenced by:  pm1.5 259  orass 260  or4 264  ordzsl 3116  posex 5908
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7
This theorem depends on definitions:  df-bi 147  df-or 224
Copyright terms: Public domain