HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
Unicode version

Theorem sbequi 1230
Description: An equality theorem for substitution.
Assertion
Ref Expression
sbequi |- (x = y -> ([x / z]ph -> [y / z]ph))

Proof of Theorem sbequi
StepHypRef Expression
1 hbsb2 1229 . . . . . 6 |- (-. A.z z = x -> ([x / z]ph -> A.z[x / z]ph))
2 equvini 1170 . . . . . . . 8 |- (x = y -> E.z(x = z /\ z = y))
3 stdpc7 1182 . . . . . . . . . 10 |- (x = z -> ([x / z]ph -> ph))
4 sbequ1 1180 . . . . . . . . . 10 |- (z = y -> (ph -> [y / z]ph))
53, 4sylan9 470 . . . . . . . . 9 |- ((x = z /\ z = y) -> ([x / z]ph -> [y / z]ph))
6519.22i 1042 . . . . . . . 8 |- (E.z(x = z /\ z = y) -> E.z([x / z]ph -> [y / z]ph))
72, 6syl 10 . . . . . . 7 |- (x = y -> E.z([x / z]ph -> [y / z]ph))
8 19.35 1077 . . . . . . 7 |- (E.z([x / z]ph -> [y / z]ph) <-> (A.z[x / z]ph -> E.z[y / z]ph))
97, 8sylib 198 . . . . . 6 |- (x = y -> (A.z[x / z]ph -> E.z[y / z]ph))
101, 9sylan9 470 . . . . 5 |- ((-. A.z z = x /\ x = y) -> ([x / z]ph -> E.z[y / z]ph))
11 hbnae 1149 . . . . . 6 |- (-. A.z z = y -> A.z -. A.z z = y)
12 hbsb2 1229 . . . . . 6 |- (-. A.z z = y -> ([y / z]ph -> A.z[y / z]ph))
1311, 1219.9d 1039 . . . . 5 |- (-. A.z z = y -> (E.z[y / z]ph -> [y / z]ph))
1410, 13syl9 57 . . . 4 |- ((-. A.z z = x /\ x = y) -> (-. A.z z = y -> ([x / z]ph -> [y / z]ph)))
1514ex 373 . . 3 |- (-. A.z z = x -> (x = y -> (-. A.z z = y -> ([x / z]ph -> [y / z]ph))))
1615com23 32 . 2 |- (-. A.z z = x -> (-. A.z z = y -> (x = y -> ([x / z]ph -> [y / z]ph))))
17 sbequ2 1181 . . . . . 6 |- (z = x -> ([x / z]ph -> ph))
1817a4s 986 . . . . 5 |- (A.z z = x -> ([x / z]ph -> ph))
1918adantr 391 . . . 4 |- ((A.z z = x /\ x = y) -> ([x / z]ph -> ph))
20 sbequ1 1180 . . . . 5 |- (x = y -> (ph -> [y / x]ph))
21 drsb1 1177 . . . . . . 7 |- (A.x x = z -> ([y / x]ph <-> [y / z]ph))
2221biimpd 153 . . . . . 6 |- (A.x x = z -> ([y / x]ph -> [y / z]ph))
2322alequcoms 1145 . . . . 5 |- (A.z z = x -> ([y / x]ph -> [y / z]ph))
2420, 23sylan9r 471 . . . 4 |- ((A.z z = x /\ x = y) -> (ph -> [y / z]ph))
2519, 24syld 27 . . 3 |- ((A.z z = x /\ x = y) -> ([x / z]ph -> [y / z]ph))
2625ex 373 . 2 |- (A.z z = x -> (x = y -> ([x / z]ph -> [y / z]ph)))
27 drsb1 1177 . . . . . 6 |- (A.z z = y -> ([x / z]ph <-> [x / y]ph))
2827biimpd 153 . . . . 5 |- (A.z z = y -> ([x / z]ph -> [x / y]ph))
29 stdpc7 1182 . . . . 5 |- (x = y -> ([x / y]ph -> ph))
3028, 29sylan9 470 . . . 4 |- ((A.z z = y /\ x = y) -> ([x / z]ph -> ph))
314a4s 986 . . . . 5 |- (A.z z = y -> (ph -> [y / z]ph))
3231adantr 391 . . . 4 |- ((A.z z = y /\ x = y) -> (ph -> [y / z]ph))
3330, 32syld 27 . . 3 |- ((A.z z = y /\ x = y) -> ([x / z]ph -> [y / z]ph))
3433ex 373 . 2 |- (A.z z = y -> (x = y -> ([x / z]ph -> [y / z]ph)))
3516, 26, 34pm2.61ii 130 1 |- (x = y -> ([x / z]ph -> [y / z]ph))
Colors of variables: wff set class
Syntax hints:  -. wn 2   -> wi 3   /\ wa 223  A.wal 956   = wceq 958  E.wex 982  [wsbc 1172
This theorem is referenced by:  sbequ 1231  drsb2 1232
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-9 967  ax-10 968  ax-12 970  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-11o 1220
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 983  df-sb 1174
Copyright terms: Public domain