HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
Unicode version

Theorem sbhyp 1940
Description: Change variable of an implicit substitution hypothesis, introducing an explicit substitution. (Contributed by Raph Levien, 10-Apr-2004.)
Hypothesis
Ref Expression
sbhyp.1 |- (x = A -> (ph <-> ps))
Assertion
Ref Expression
sbhyp |- (y = A -> ([y / x]ph <-> ps))
Distinct variable groups:   ps,x   x,A   x,y

Proof of Theorem sbhyp
StepHypRef Expression
1 visset 1813 . . 3 |- y e. V
2 eqeq1 1481 . . 3 |- (x = y -> (x = A <-> y = A))
31, 2ceqsexv 1835 . 2 |- (E.x(x = y /\ x = A) <-> y = A)
4 hbs1 1332 . . . 4 |- ([y / x]ph -> A.x[y / x]ph)
5 ax-17 971 . . . 4 |- (ps -> A.xps)
64, 5hbbi 1010 . . 3 |- (([y / x]ph <-> ps) -> A.x([y / x]ph <-> ps))
7 sbequ12 1181 . . . . 5 |- (x = y -> (ph <-> [y / x]ph))
87bicomd 521 . . . 4 |- (x = y -> ([y / x]ph <-> ph))
9 sbhyp.1 . . . 4 |- (x = A -> (ph <-> ps))
108, 9sylan9bb 540 . . 3 |- ((x = y /\ x = A) -> ([y / x]ph <-> ps))
116, 1019.23ai 1064 . 2 |- (E.x(x = y /\ x = A) -> ([y / x]ph <-> ps))
123, 11sylbir 201 1 |- (y = A -> ([y / x]ph <-> ps))
Colors of variables: wff set class
Syntax hints:   -> wi 3   <-> wb 146   /\ wa 223   = wceq 956  E.wex 980  [wsbc 1170
This theorem is referenced by:  nn0ind-raph 6214
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 962  ax-gen 963  ax-10 966  ax-12 968  ax-17 971  ax-4 973  ax-5o 975  ax-6o 978  ax-9o 1123  ax-10o 1140  ax-16 1210  ax-11o 1218  ax-ext 1459
This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 981  df-sb 1172  df-clab 1464  df-cleq 1469  df-clel 1472  df-v 1812
Copyright terms: Public domain