Theorem sbimi 1169

Description: Infer substitution into antecedent and consequent of an implication.

Hypothesis

Ref	Expression
sbimi.1	|- (ph -> ps)

Assertion

Ref	Expression
sbimi	|- ([y / x]ph -> [y / x]ps)

Proof of Theorem sbimi

Step	Hyp	Ref	Expression
1		sbimi.1	. . . 4 |- (ph -> ps)
2	1	imim2i 17	. . 3 |- ((x = y -> ph) -> (x = y -> ps))
3	1	anim2i 335	. . . 4 |- ((x = y /\ ph) -> (x = y /\ ps))
4	3	19.22i 1036	. . 3 |- (E.x(x = y /\ ph) -> E.x(x = y /\ ps))
5	2, 4	anim12i 333	. 2 |- (((x = y -> ph) /\ E.x(x = y /\ ph)) -> ((x = y -> ps) /\ E.x(x = y /\ ps)))
6		df-sb 1168	. 2 |- ([y / x]ph <-> ((x = y -> ph) /\ E.x(x = y /\ ph)))
7		df-sb 1168	. 2 |- ([y / x]ps <-> ((x = y -> ps) /\ E.x(x = y /\ ps)))
8	5, 6, 7	3imtr4 219	1 |- ([y / x]ph -> [y / x]ps)

Syntax hints:   -> wi 3   /\ wa 223  E.wex 977  [wsbc 1166

This theorem is referenced by:  sbbii 1170  sb6f 1197  hbsb3 1202  sbi2 1228  sbco 1247  equsb3lem 1324  elsb3 1326  sbal1 1341  sbal 1342  tfinds2 3155  csbfsum 6965

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 960  ax-4 970  ax-5o 972

This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 978  df-sb 1168

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