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Theorem staffn 15630
Description: The functionalization is equal to the original function, if it is a function on the right base set. (Contributed by Mario Carneiro, 6-Oct-2015.)
Hypotheses
Ref Expression
staffval.b  |-  B  =  ( Base `  R
)
staffval.i  |-  .*  =  ( * r `  R )
staffval.f  |-  .xb  =  ( * r f `
 R )
Assertion
Ref Expression
staffn  |-  (  .*  Fn  B  ->  .xb  =  .*  )

Proof of Theorem staffn
Dummy variable  x is distinct from all other variables.
StepHypRef Expression
1 dffn5 5584 . . 3  |-  (  .*  Fn  B  <->  .*  =  ( x  e.  B  |->  (  .*  `  x
) ) )
21biimpi 186 . 2  |-  (  .*  Fn  B  ->  .*  =  ( x  e.  B  |->  (  .*  `  x
) ) )
3 staffval.b . . 3  |-  B  =  ( Base `  R
)
4 staffval.i . . 3  |-  .*  =  ( * r `  R )
5 staffval.f . . 3  |-  .xb  =  ( * r f `
 R )
63, 4, 5staffval 15628 . 2  |-  .xb  =  ( x  e.  B  |->  (  .*  `  x
) )
72, 6syl6reqr 2347 1  |-  (  .*  Fn  B  ->  .xb  =  .*  )
Colors of variables: wff set class
Syntax hints:    -> wi 4    = wceq 1632    e. cmpt 4093    Fn wfn 5266   ` cfv 5271   Basecbs 13164   * rcstv 13226   * r fcstf 15624
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-3 7  ax-mp 8  ax-gen 1536  ax-5 1547  ax-17 1606  ax-9 1644  ax-8 1661  ax-13 1698  ax-14 1700  ax-6 1715  ax-7 1720  ax-11 1727  ax-12 1878  ax-ext 2277  ax-sep 4157  ax-nul 4165  ax-pow 4204  ax-pr 4230  ax-un 4528
This theorem depends on definitions:  df-bi 177  df-or 359  df-an 360  df-3an 936  df-tru 1310  df-ex 1532  df-nf 1535  df-sb 1639  df-eu 2160  df-mo 2161  df-clab 2283  df-cleq 2289  df-clel 2292  df-nfc 2421  df-ne 2461  df-ral 2561  df-rex 2562  df-rab 2565  df-v 2803  df-sbc 3005  df-dif 3168  df-un 3170  df-in 3172  df-ss 3179  df-nul 3469  df-if 3579  df-pw 3640  df-sn 3659  df-pr 3660  df-op 3662  df-uni 3844  df-br 4040  df-opab 4094  df-mpt 4095  df-id 4325  df-xp 4711  df-rel 4712  df-cnv 4713  df-co 4714  df-dm 4715  df-rn 4716  df-res 4717  df-ima 4718  df-iota 5235  df-fun 5273  df-fn 5274  df-f 5275  df-fv 5279  df-staf 15626
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