HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
GIF version

Theorem 19.31 1089
Description: Theorem 19.31 of [Margaris] p. 90.
Hypothesis
Ref Expression
19.31.1 (ψxψ)
Assertion
Ref Expression
19.31 (x(φ ψ) ↔ (xφ ψ))

Proof of Theorem 19.31
StepHypRef Expression
1 19.31.1 . . 3 (ψxψ)
2119.32 1088 . 2 (x(ψ φ) ↔ (ψ xφ))
3 orcom 246 . . 3 ((φ ψ) ↔ (ψ φ))
43albii 1001 . 2 (x(φ ψ) ↔ x(ψ φ))
5 orcom 246 . 2 ((xφ ψ) ↔ (ψ xφ))
62, 4, 53bitr4 183 1 (x(φ ψ) ↔ (xφ ψ))
Colors of variables: wff set class
Syntax hints:   → wi 3   ↔ wb 146   wo 222  wal 956
This theorem is referenced by:  19.41 1097  2eu3 1454
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 965  ax-4 975  ax-5o 977  ax-6o 980
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225
Copyright terms: Public domain