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Theorem 2sb6 1338
Description: Equivalence for double substitution.
Assertion
Ref Expression
2sb6 ([z / x][w / y]φxy((x = z y = w) → φ))
Distinct variable groups:   x,y,z   y,w

Proof of Theorem 2sb6
StepHypRef Expression
1 sb6 1269 . 2 ([z / x][w / y]φx(x = z → [w / y]φ))
2 19.21v 1287 . . . 4 (y(x = z → (y = wφ)) ↔ (x = zy(y = wφ)))
3 impexp 347 . . . . 5 (((x = z y = w) → φ) ↔ (x = z → (y = wφ)))
43albii 1001 . . . 4 (y((x = z y = w) → φ) ↔ y(x = z → (y = wφ)))
5 sb6 1269 . . . . 5 ([w / y]φy(y = wφ))
65imbi2i 185 . . . 4 ((x = z → [w / y]φ) ↔ (x = zy(y = wφ)))
72, 4, 63bitr4r 184 . . 3 ((x = z → [w / y]φ) ↔ y((x = z y = w) → φ))
87albii 1001 . 2 (x(x = z → [w / y]φ) ↔ xy((x = z y = w) → φ))
91, 8bitr 173 1 ([z / x][w / y]φxy((x = z y = w) → φ))
Colors of variables: wff set class
Syntax hints:   → wi 3   ↔ wb 146   wa 223  wal 956   = wceq 958  [wsbc 1172
This theorem is referenced by:  2eu6 1457
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-gen 965  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-16 1212  ax-11o 1220
This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 983  df-sb 1174
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