Proof of Theorem 2sb6
| Step | Hyp | Ref
| Expression |
| 1 | | sb6 1269 |
. 2
⊢ ([z / x][w / y]φ ↔ ∀x(x = z →
[w / y]φ)) |
| 2 | | 19.21v 1287 |
. . . 4
⊢ (∀y(x = z →
(y = w
→ φ)) ↔ (x = z →
∀y(y = w → φ))) |
| 3 | | impexp 347 |
. . . . 5
⊢ (((x = z ⋀ y = w) → φ)
↔ (x = z → (y =
w → φ))) |
| 4 | 3 | albii 1001 |
. . . 4
⊢ (∀y((x = z ⋀ y = w) → φ)
↔ ∀y(x = z → (y =
w → φ))) |
| 5 | | sb6 1269 |
. . . . 5
⊢ ([w / y]φ ↔ ∀y(y = w →
φ)) |
| 6 | 5 | imbi2i 185 |
. . . 4
⊢ ((x = z →
[w / y]φ) ↔
(x = z
→ ∀y(y = w → φ))) |
| 7 | 2, 4, 6 | 3bitr4r 184 |
. . 3
⊢ ((x = z →
[w / y]φ) ↔
∀y((x = z ⋀ y = w) →
φ)) |
| 8 | 7 | albii 1001 |
. 2
⊢ (∀x(x = z →
[w / y]φ) ↔
∀x∀y((x = z ⋀ y = w) → φ)) |
| 9 | 1, 8 | bitr 173 |
1
⊢ ([z / x][w / y]φ ↔ ∀x∀y((x = z ⋀ y = w) → φ)) |