HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
GIF version

Theorem 2sb6rf 1341
Description: Reversed double substitution.
Hypotheses
Ref Expression
2sb5rf.1 (φzφ)
2sb5rf.2 (φwφ)
Assertion
Ref Expression
2sb6rf (φzw((z = x w = y) → [z / x][w / y]φ))
Distinct variable groups:   x,y   x,w   y,z   z,w

Proof of Theorem 2sb6rf
StepHypRef Expression
1 2sb5rf.1 . . 3 (φzφ)
21sb6rf 1262 . 2 (φz(z = x → [z / x]φ))
3 19.21v 1287 . . . 4 (w(z = x → (w = y → [w / y][z / x]φ)) ↔ (z = xw(w = y → [w / y][z / x]φ)))
4 sbcom2 1336 . . . . . . 7 ([z / x][w / y]φ ↔ [w / y][z / x]φ)
54imbi2i 185 . . . . . 6 (((z = x w = y) → [z / x][w / y]φ) ↔ ((z = x w = y) → [w / y][z / x]φ))
6 impexp 347 . . . . . 6 (((z = x w = y) → [w / y][z / x]φ) ↔ (z = x → (w = y → [w / y][z / x]φ)))
75, 6bitr 173 . . . . 5 (((z = x w = y) → [z / x][w / y]φ) ↔ (z = x → (w = y → [w / y][z / x]φ)))
87albii 1001 . . . 4 (w((z = x w = y) → [z / x][w / y]φ) ↔ w(z = x → (w = y → [w / y][z / x]φ)))
9 2sb5rf.2 . . . . . . 7 (φwφ)
109hbsb 1335 . . . . . 6 ([z / x]φw[z / x]φ)
1110sb6rf 1262 . . . . 5 ([z / x]φw(w = y → [w / y][z / x]φ))
1211imbi2i 185 . . . 4 ((z = x → [z / x]φ) ↔ (z = xw(w = y → [w / y][z / x]φ)))
133, 8, 123bitr4r 184 . . 3 ((z = x → [z / x]φ) ↔ w((z = x w = y) → [z / x][w / y]φ))
1413albii 1001 . 2 (z(z = x → [z / x]φ) ↔ zw((z = x w = y) → [z / x][w / y]φ))
152, 14bitr 173 1 (φzw((z = x w = y) → [z / x][w / y]φ))
Colors of variables: wff set class
Syntax hints:   → wi 3   ↔ wb 146   wa 223  wal 956   = wceq 958  [wsbc 1172
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-10 968  ax-12 970  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-16 1212  ax-11o 1220
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 983  df-sb 1174
Copyright terms: Public domain