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Theorem dfss4 2232
Description: Subclass defined in terms of class difference. See comments under dfun2 2233.
Assertion
Ref Expression
dfss4 (AB ↔ (B ∖ (BA)) = A)

Proof of Theorem dfss4
StepHypRef Expression
1 sseqin2 2219 . 2 (AB ↔ (BA) = A)
2 abai 478 . . . . . 6 ((xBxA) ↔ (xB ⋀ (xBxA)))
3 iman 237 . . . . . . 7 ((xBxA) ↔ ¬ (xB ⋀ ¬ xA))
43anbi2i 479 . . . . . 6 ((xB ⋀ (xBxA)) ↔ (xB ⋀ ¬ (xB ⋀ ¬ xA)))
52, 4bitr 173 . . . . 5 ((xBxA) ↔ (xB ⋀ ¬ (xB ⋀ ¬ xA)))
6 elin 2197 . . . . 5 (x ∈ (BA) ↔ (xBxA))
7 eldif 2047 . . . . . 6 (x ∈ (B ∖ (BA)) ↔ (xB ⋀ ¬ x ∈ (BA)))
8 eldif 2047 . . . . . . . 8 (x ∈ (BA) ↔ (xB ⋀ ¬ xA))
98negbii 187 . . . . . . 7 x ∈ (BA) ↔ ¬ (xB ⋀ ¬ xA))
109anbi2i 479 . . . . . 6 ((xB ⋀ ¬ x ∈ (BA)) ↔ (xB ⋀ ¬ (xB ⋀ ¬ xA)))
117, 10bitr 173 . . . . 5 (x ∈ (B ∖ (BA)) ↔ (xB ⋀ ¬ (xB ⋀ ¬ xA)))
125, 6, 113bitr4 183 . . . 4 (x ∈ (BA) ↔ x ∈ (B ∖ (BA)))
1312eqriv 1467 . . 3 (BA) = (B ∖ (BA))
1413eqeq1i 1474 . 2 ((BA) = A ↔ (B ∖ (BA)) = A)
151, 14bitr 173 1 (AB ↔ (B ∖ (BA)) = A)
Colors of variables: wff set class
Syntax hints:  ¬ wn 2   → wi 3   ↔ wb 146   ⋀ wa 223   = wceq 953   ∈ wcel 955   ∖ cdif 2034   ∩ cin 2036   ⊆ wss 2037
This theorem is referenced by:  dfin4 2238  sbthlem3 4429  isopn2 7615  iincld 7621  ntrval2 7628  cmclsopn 7635  cmntrcld 7636  islp2 7688
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 959  ax-gen 960  ax-8 961  ax-10 963  ax-12 965  ax-17 968  ax-4 970  ax-5o 972  ax-6o 975  ax-9o 1119  ax-10o 1136  ax-16 1206  ax-11o 1213  ax-ext 1452
This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 978  df-sb 1168  df-clab 1457  df-cleq 1462  df-clel 1465  df-v 1803  df-dif 2039  df-in 2041  df-ss 2043
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