HomeHome Metamath Proof Explorer < Previous   Next >
Related theorems
GIF version

Theorem exmoeu 1415
Description: Existence in terms of "at most one" and uniqueness.
Assertion
Ref Expression
exmoeu (xφ ↔ (∃*xφ∃!xφ))

Proof of Theorem exmoeu
StepHypRef Expression
1 df-mo 1385 . . . 4 (∃*xφ ↔ (xφ∃!xφ))
21biimp 151 . . 3 (∃*xφ → (xφ∃!xφ))
32com12 11 . 2 (xφ → (∃*xφ∃!xφ))
41biimpr 152 . . . 4 ((xφ∃!xφ) → ∃*xφ)
5 euex 1396 . . . 4 (∃!xφxφ)
64, 5imim12i 18 . . 3 ((∃*xφ∃!xφ) → ((xφ∃!xφ) → xφ))
7 peirce 82 . . 3 (((xφ∃!xφ) → xφ) → xφ)
86, 7syl 10 . 2 ((∃*xφ∃!xφ) → xφ)
93, 8impbi 157 1 (xφ ↔ (∃*xφ∃!xφ))
Colors of variables: wff set class
Syntax hints:   → wi 3   ↔ wb 146  wex 982  ∃!weu 1382  ∃*wmo 1383
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-10 968  ax-11 969  ax-12 970  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-16 1212  ax-11o 1220
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 983  df-sb 1174  df-eu 1384  df-mo 1385
Copyright terms: Public domain