Proof of Theorem intprd
| Step | Hyp | Ref
| Expression |
| 1 | | preq1 2438 |
. . . 4
⊢ (A =
if(A ∈ V, A, ∅) → {A, B} = {
if(A ∈ V, A, ∅), B}) |
| 2 | 1 | inteqd 2528 |
. . 3
⊢ (A =
if(A ∈ V, A, ∅) → ∩{A, B} = ∩{ if(A ∈ V, A, ∅), B}) |
| 3 | | ineq1 2200 |
. . 3
⊢ (A =
if(A ∈ V, A, ∅) → (A ∩ B) = (
if(A ∈ V, A, ∅) ∩ B)) |
| 4 | 2, 3 | eqeq12d 1481 |
. 2
⊢ (A =
if(A ∈ V, A, ∅) → (∩{A, B} = (A ∩
B) ↔ ∩{
if(A ∈ V, A, ∅), B}
= ( if(A ∈ V, A, ∅) ∩ B))) |
| 5 | | preq2 2439 |
. . . 4
⊢ (B =
if(B ∈ V, B, ∅) → { if(A ∈ V, A, ∅), B}
= { if(A ∈ V, A, ∅), if(B ∈ V, B, ∅)}) |
| 6 | 5 | inteqd 2528 |
. . 3
⊢ (B =
if(B ∈ V, B, ∅) → ∩{
if(A ∈ V, A, ∅), B}
= ∩{ if(A ∈
V, A, ∅), if(B ∈ V, B, ∅)}) |
| 7 | | ineq2 2201 |
. . 3
⊢ (B =
if(B ∈ V, B, ∅) → ( if(A ∈ V, A, ∅) ∩ B) = ( if(A
∈ V, A, ∅) ∩
if(B ∈ V, B, ∅))) |
| 8 | 6, 7 | eqeq12d 1481 |
. 2
⊢ (B =
if(B ∈ V, B, ∅) → (∩{
if(A ∈ V, A, ∅), B}
= ( if(A ∈ V, A, ∅) ∩ B) ↔ ∩{ if(A ∈ V, A, ∅), if(B ∈ V, B, ∅)} = ( if(A ∈ V, A, ∅) ∩ if(B ∈ V, B, ∅)))) |
| 9 | | 0ex 2701 |
. . . 4
⊢ ∅ ∈ V |
| 10 | 9 | elimel 2384 |
. . 3
⊢ if(A
∈ V, A, ∅) ∈
V |
| 11 | 9 | elimel 2384 |
. . 3
⊢ if(B
∈ V, B, ∅) ∈
V |
| 12 | 10, 11 | intpr 2553 |
. 2
⊢ ∩{ if(A ∈ V, A, ∅), if(B ∈ V, B, ∅)} = ( if(A ∈ V, A, ∅) ∩ if(B ∈ V, B, ∅)) |
| 13 | 4, 8, 12 | dedth2h 2377 |
1
⊢ ((A
∈ V ⋀ B ∈ V)
→ ∩{A,
B} = (A
∩ B)) |