Proof of Theorem pwsnALT
| Step | Hyp | Ref
| Expression |
| 1 | | dfss2 2061 |
. . . . . . . . 9
⊢ (x ⊆ {A} ↔ ∀y(y ∈ x → y ∈ {A})) |
| 2 | | elsn 2425 |
. . . . . . . . . . 11
⊢ (y ∈ {A} ↔ y =
A) |
| 3 | 2 | imbi2i 185 |
. . . . . . . . . 10
⊢ ((y ∈ x → y ∈ {A}) ↔
(y ∈
x → y = A)) |
| 4 | 3 | albii 1001 |
. . . . . . . . 9
⊢ (∀y(y ∈ x → y ∈ {A}) ↔
∀y(y ∈ x →
y = A)) |
| 5 | 1, 4 | bitr 173 |
. . . . . . . 8
⊢ (x ⊆ {A} ↔ ∀y(y ∈ x → y =
A)) |
| 6 | | exintr 1119 |
. . . . . . . . . 10
⊢ (∀y(y ∈ x → y =
A) → (∃y y ∈ x → ∃y(y ∈ x ⋀ y = A))) |
| 7 | | n0 2293 |
. . . . . . . . . 10
⊢ (¬ x = ∅ ↔
∃y
y ∈
x) |
| 8 | 6, 7 | syl5ib 206 |
. . . . . . . . 9
⊢ (∀y(y ∈ x → y =
A) → (¬ x = ∅ →
∃y(y ∈ x ⋀ y = A))) |
| 9 | | df-clel 1475 |
. . . . . . . . . . 11
⊢ (A ∈ x ↔ ∃y(y = A ⋀ y ∈ x)) |
| 10 | | exancom 1056 |
. . . . . . . . . . 11
⊢ (∃y(y = A ⋀ y ∈ x) ↔
∃y(y ∈ x ⋀ y = A)) |
| 11 | 9, 10 | bitr2 174 |
. . . . . . . . . 10
⊢ (∃y(y ∈ x ⋀ y = A) ↔
A ∈
x) |
| 12 | | snssi 2470 |
. . . . . . . . . 10
⊢ (A ∈ x → {A}
⊆ x) |
| 13 | 11, 12 | sylbi 199 |
. . . . . . . . 9
⊢ (∃y(y ∈ x ⋀ y = A) →
{A} ⊆
x) |
| 14 | 8, 13 | syl6 22 |
. . . . . . . 8
⊢ (∀y(y ∈ x → y =
A) → (¬ x = ∅ →
{A} ⊆
x)) |
| 15 | 5, 14 | sylbi 199 |
. . . . . . 7
⊢ (x ⊆ {A} → (¬ x = ∅ →
{A} ⊆
x)) |
| 16 | 15 | anc2li 302 |
. . . . . 6
⊢ (x ⊆ {A} → (¬ x = ∅ →
(x ⊆
{A} ⋀
{A} ⊆
x))) |
| 17 | | eqss 2080 |
. . . . . 6
⊢ (x = {A} ↔
(x ⊆
{A} ⋀
{A} ⊆
x)) |
| 18 | 16, 17 | syl6ibr 213 |
. . . . 5
⊢ (x ⊆ {A} → (¬ x = ∅ →
x = {A})) |
| 19 | 18 | orrd 233 |
. . . 4
⊢ (x ⊆ {A} → (x =
∅ ⋁
x = {A})) |
| 20 | | 0ss 2305 |
. . . . . 6
⊢ ∅ ⊆ {A} |
| 21 | | sseq1 2085 |
. . . . . 6
⊢ (x = ∅ →
(x ⊆
{A} ↔ ∅ ⊆ {A})) |
| 22 | 20, 21 | mpbiri 194 |
. . . . 5
⊢ (x = ∅ →
x ⊆
{A}) |
| 23 | | eqimss 2112 |
. . . . 5
⊢ (x = {A} →
x ⊆
{A}) |
| 24 | 22, 23 | jaoi 341 |
. . . 4
⊢ ((x = ∅ ⋁ x =
{A}) → x ⊆ {A}) |
| 25 | 19, 24 | impbi 157 |
. . 3
⊢ (x ⊆ {A} ↔ (x =
∅ ⋁
x = {A})) |
| 26 | 25 | abbii 1578 |
. 2
⊢ {x∣x ⊆ {A}} = {x∣(x = ∅ ⋁ x = {A})} |
| 27 | | df-pw 2406 |
. 2
⊢ ℘{A} =
{x∣x ⊆ {A}} |
| 28 | | dfpr2 2426 |
. 2
⊢ {∅, {A}} =
{x∣(x = ∅ ⋁ x = {A})} |
| 29 | 26, 27, 28 | 3eqtr4 1508 |
1
⊢ ℘{A} = {∅, {A}} |