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Theorem rabss 2127
Description: Restricted class abstraction in a subclass relationship.
Assertion
Ref Expression
rabss ({x Aφ} Bx A (φx B))
Distinct variable group:   x,B

Proof of Theorem rabss
StepHypRef Expression
1 df-rab 1655 . . 3 {x Aφ} = {x(x A φ)}
21sseq1i 2088 . 2 ({x Aφ} B ↔ {x(x A φ)} B)
3 abss 2120 . 2 ({x(x A φ)} Bx((x A φ) → x B))
4 impexp 347 . . . 4 (((x A φ) → x B) ↔ (x A → (φx B)))
54albii 1001 . . 3 (x((x A φ) → x B) ↔ x(x A → (φx B)))
6 df-ral 1652 . . 3 (x A (φx B) ↔ x(x A → (φx B)))
75, 6bitr4 176 . 2 (x((x A φ) → x B) ↔ x A (φx B))
82, 3, 73bitr 177 1 ({x Aφ} Bx A (φx B))
Colors of variables: wff set class
Syntax hints:   → wi 3   ↔ wb 146   wa 223  wal 956   wcel 960  {cab 1466  wral 1648  {crab 1651   wss 2050
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-10 968  ax-12 970  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-16 1212  ax-11o 1220  ax-ext 1462
This theorem depends on definitions:  df-bi 147  df-an 225  df-ex 983  df-sb 1174  df-clab 1467  df-cleq 1472  df-clel 1475  df-ral 1652  df-rab 1655  df-in 2054  df-ss 2056
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