Proof of Theorem ralidm
| Step | Hyp | Ref
| Expression |
| 1 | | pm5.1 688 |
. . 3
⊢ ((∀x ∈ A ∀x ∈ A φ ⋀ ∀x ∈ A φ) → (∀x ∈ A ∀x ∈ A φ ↔ ∀x ∈ A φ)) |
| 2 | | rzal 2407 |
. . 3
⊢ (A = ∅ →
∀x
∈ A ∀x ∈ A φ) |
| 3 | | rzal 2407 |
. . 3
⊢ (A = ∅ →
∀x
∈ A φ) |
| 4 | 1, 2, 3 | sylanc 482 |
. 2
⊢ (A = ∅ →
(∀x
∈ A ∀x ∈ A φ ↔ ∀x ∈ A φ)) |
| 5 | | n0 2341 |
. . 3
⊢ (¬ A = ∅ ↔
∃x
x ∈
A) |
| 6 | | biimt 743 |
. . . 4
⊢ (∃x x ∈ A → (∀x ∈ A φ ↔ (∃x x ∈ A → ∀x ∈ A φ))) |
| 7 | | df-ral 1696 |
. . . . 5
⊢ (∀x ∈ A ∀x ∈ A φ ↔ ∀x(x ∈ A → ∀x ∈ A φ)) |
| 8 | | hbra1 1734 |
. . . . . 6
⊢ (∀x ∈ A φ → ∀x∀x ∈ A φ) |
| 9 | 8 | 19.23 1104 |
. . . . 5
⊢ (∀x(x ∈ A → ∀x ∈ A φ) ↔ (∃x x ∈ A → ∀x ∈ A φ)) |
| 10 | 7, 9 | bitri 180 |
. . . 4
⊢ (∀x ∈ A ∀x ∈ A φ ↔ (∃x x ∈ A → ∀x ∈ A φ)) |
| 11 | 6, 10 | syl6rbbr 550 |
. . 3
⊢ (∃x x ∈ A → (∀x ∈ A ∀x ∈ A φ ↔ ∀x ∈ A φ)) |
| 12 | 5, 11 | sylbi 206 |
. 2
⊢ (¬ A = ∅ →
(∀x
∈ A ∀x ∈ A φ ↔ ∀x ∈ A φ)) |
| 13 | 4, 12 | pm2.61i 132 |
1
⊢ (∀x ∈ A ∀x ∈ A φ ↔ ∀x ∈ A φ) |