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GIF version

Theorem ralpr 2432
Description: Convert a quantification over a pair to a conjunction.
Hypotheses
Ref Expression
ralpr.1 A V
ralpr.2 B V
Assertion
Ref Expression
ralpr (x {A, B}φ ↔ ([A / x]φ [B / x]φ))
Distinct variable groups:   x,A   x,B

Proof of Theorem ralpr
StepHypRef Expression
1 df-ral 1652 . 2 (x {A, B}φx(x {A, B} → φ))
2 visset 1816 . . . . . 6 x V
32elpr 2428 . . . . 5 (x {A, B} ↔ (x = A x = B))
43imbi1i 186 . . . 4 ((x {A, B} → φ) ↔ ((x = A x = B) → φ))
5 jaob 424 . . . 4 (((x = A x = B) → φ) ↔ ((x = Aφ) (x = Bφ)))
64, 5bitr 173 . . 3 ((x {A, B} → φ) ↔ ((x = Aφ) (x = Bφ)))
76albii 1001 . 2 (x(x {A, B} → φ) ↔ x((x = Aφ) (x = Bφ)))
8 19.26 1069 . . 3 (x((x = Aφ) (x = Bφ)) ↔ (x(x = Aφ) x(x = Bφ)))
9 ralpr.1 . . . . 5 A V
109sbc6 1960 . . . 4 ([A / x]φx(x = Aφ))
11 ralpr.2 . . . . 5 B V
1211sbc6 1960 . . . 4 ([B / x]φx(x = Bφ))
1310, 12anbi12i 484 . . 3 (([A / x]φ [B / x]φ) ↔ (x(x = Aφ) x(x = Bφ)))
148, 13bitr4 176 . 2 (x((x = Aφ) (x = Bφ)) ↔ ([A / x]φ [B / x]φ))
151, 7, 143bitr 177 1 (x {A, B}φ ↔ ([A / x]φ [B / x]φ))
Colors of variables: wff set class
Syntax hints:   → wi 3   ↔ wb 146   wo 222   wa 223  wal 956   = wceq 958   wcel 960  [wsbc 1172  wral 1648  Vcvv 1814  {cpr 2414
This theorem is referenced by:  rexpr 2433
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-10 968  ax-12 970  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-16 1212  ax-11o 1220  ax-ext 1462
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 983  df-sb 1174  df-clab 1467  df-cleq 1472  df-clel 1475  df-ral 1652  df-v 1815  df-sbc 1945  df-un 2053  df-sn 2416  df-pr 2417
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