Theorem rescom 3390

Description: Commutative law for restriction.

Assertion

Ref	Expression
rescom	⊢ ((A ↾ B) ↾ C) = ((A ↾ C) ↾ B)

Proof of Theorem rescom

Step	Hyp	Ref	Expression
1		incom 2211	. . 3 ⊢ (B ∩ C) = (C ∩ B)
2		reseq2 3375	. . 3 ⊢ ((B ∩ C) = (C ∩ B) → (A ↾ (B ∩ C)) = (A ↾ (C ∩ B)))
3	1, 2	ax-mp 7	. 2 ⊢ (A ↾ (B ∩ C)) = (A ↾ (C ∩ B))
4		resres 3383	. 2 ⊢ ((A ↾ B) ↾ C) = (A ↾ (B ∩ C))
5		resres 3383	. 2 ⊢ ((A ↾ C) ↾ B) = (A ↾ (C ∩ B))
6	3, 4, 5	3eqtr4 1508	1 ⊢ ((A ↾ B) ↾ C) = ((A ↾ C) ↾ B)

Syntax hints:   = wceq 958   ∩ cin 2049   ↾ cres 3178

This theorem is referenced by:  resabs2 3395

This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-10 968  ax-11 969  ax-12 970  ax-13 971  ax-14 972  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-16 1212  ax-11o 1220  ax-ext 1462  ax-sep 2708  ax-pow 2748  ax-pr 2785

This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-ex 983  df-sb 1174  df-eu 1384  df-mo 1385  df-clab 1467  df-cleq 1472  df-clel 1475  df-ne 1590  df-v 1815  df-dif 2052  df-un 2053  df-in 2054  df-ss 2056  df-nul 2284  df-pw 2406  df-sn 2416  df-pr 2417  df-op 2420  df-opab 2672  df-xp 3190  df-rel 3191  df-res 3196

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