Proof of Theorem ring2
| Step | Hyp | Ref
| Expression |
| 1 | | ring2.1 |
. . . 4
⊢ G = (1st ‘R) |
| 2 | | ring2.2 |
. . . 4
⊢ H = (2nd ‘R) |
| 3 | | ring2.3 |
. . . 4
⊢ X = ran G |
| 4 | 1, 2, 3 | ringid 8141 |
. . 3
⊢ ((R ∈ Ring ⋀ A ∈ X) →
∃x ∈ X ((AHx) = A ⋀ (xHA) = A)) |
| 5 | | pm3.27 323 |
. . . 4
⊢ (((AHx) = A ⋀ (xHA) = A) → (xHA) = A) |
| 6 | 5 | r19.22si 1737 |
. . 3
⊢ (∃x ∈ X ((AHx) = A ⋀ (xHA) = A) → ∃x ∈ X (xHA) = A) |
| 7 | | opreq12 3976 |
. . . . 5
⊢ (((xHA) = A ⋀ (xHA) = A) → ((xHA)G(xHA)) = (AGA)) |
| 8 | 7 | anidms 436 |
. . . 4
⊢ ((xHA) = A →
((xHA)G(xHA)) = (AGA)) |
| 9 | 8 | r19.22si 1737 |
. . 3
⊢ (∃x ∈ X (xHA) = A →
∃x ∈ X ((xHA)G(xHA)) = (AGA)) |
| 10 | 4, 6, 9 | 3syl 20 |
. 2
⊢ ((R ∈ Ring ⋀ A ∈ X) →
∃x ∈ X ((xHA)G(xHA)) = (AGA)) |
| 11 | | eqtrt 1495 |
. . . . . . 7
⊢ ((((xGx)HA) = ((xHA)G(xHA)) ⋀ ((xHA)G(xHA)) = (AGA)) → ((xGx)HA) = (AGA)) |
| 12 | 11 | eqcomd 1483 |
. . . . . 6
⊢ ((((xGx)HA) = ((xHA)G(xHA)) ⋀ ((xHA)G(xHA)) = (AGA)) → (AGA) = ((xGx)HA)) |
| 13 | 1, 2, 3 | ringdir 8143 |
. . . . . . . . . . 11
⊢ ((R ∈ Ring ⋀ (x ∈ X ⋀ x ∈ X ⋀ A ∈ X)) →
((xGx)HA) = ((xHA)G(xHA))) |
| 14 | 13 | expcom 374 |
. . . . . . . . . 10
⊢ ((x ∈ X ⋀ x ∈ X ⋀ A ∈ X) → (R
∈ Ring → ((xGx)HA) = ((xHA)G(xHA)))) |
| 15 | 14 | 3expia 837 |
. . . . . . . . 9
⊢ ((x ∈ X ⋀ x ∈ X) → (A
∈ X
→ (R ∈ Ring → ((xGx)HA) = ((xHA)G(xHA))))) |
| 16 | 15 | anidms 436 |
. . . . . . . 8
⊢ (x ∈ X → (A
∈ X
→ (R ∈ Ring → ((xGx)HA) = ((xHA)G(xHA))))) |
| 17 | 16 | 3imp 829 |
. . . . . . 7
⊢ ((x ∈ X ⋀ A ∈ X ⋀ R ∈ Ring) →
((xGx)HA) = ((xHA)G(xHA))) |
| 18 | 17 | 3com13 840 |
. . . . . 6
⊢ ((R ∈ Ring ⋀ A ∈ X ⋀ x ∈ X) →
((xGx)HA) = ((xHA)G(xHA))) |
| 19 | 12, 18 | sylan 450 |
. . . . 5
⊢ (((R ∈ Ring ⋀ A ∈ X ⋀ x ∈ X) ⋀ ((xHA)G(xHA)) = (AGA)) → (AGA) = ((xGx)HA)) |
| 20 | 19 | ex 373 |
. . . 4
⊢ ((R ∈ Ring ⋀ A ∈ X ⋀ x ∈ X) →
(((xHA)G(xHA)) = (AGA) → (AGA) = ((xGx)HA))) |
| 21 | 20 | 3expa 835 |
. . 3
⊢ (((R ∈ Ring ⋀ A ∈ X) ⋀ x ∈ X) →
(((xHA)G(xHA)) = (AGA) → (AGA) = ((xGx)HA))) |
| 22 | 21 | r19.22dva 1742 |
. 2
⊢ ((R ∈ Ring ⋀ A ∈ X) →
(∃x
∈ X
((xHA)G(xHA)) = (AGA) → ∃x ∈ X (AGA) = ((xGx)HA))) |
| 23 | 10, 22 | mpd 26 |
1
⊢ ((R ∈ Ring ⋀ A ∈ X) →
∃x ∈ X (AGA) = ((xGx)HA)) |