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Related theorems GIF version |
| Description: Introduce an explicit substitution into an implicit substitution hypothesis. |
| Ref | Expression |
|---|---|
| sbhypf.1 | ⊢ (ψ → ∀xψ) |
| sbhypf.2 | ⊢ (x = A → (φ ↔ ψ)) |
| Ref | Expression |
|---|---|
| sbhypf | ⊢ (y = A → ([y / x]φ ↔ ψ)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | visset 1816 | . . 3 ⊢ y ∈ V | |
| 2 | eqeq1 1484 | . . 3 ⊢ (x = y → (x = A ↔ y = A)) | |
| 3 | 1, 2 | ceqsexv 1838 | . 2 ⊢ (∃x(x = y ⋀ x = A) ↔ y = A) |
| 4 | hbs1 1334 | . . . 4 ⊢ ([y / x]φ → ∀x[y / x]φ) | |
| 5 | sbhypf.1 | . . . 4 ⊢ (ψ → ∀xψ) | |
| 6 | 4, 5 | hbbi 1012 | . . 3 ⊢ (([y / x]φ ↔ ψ) → ∀x([y / x]φ ↔ ψ)) |
| 7 | sbequ12 1183 | . . . . 5 ⊢ (x = y → (φ ↔ [y / x]φ)) | |
| 8 | 7 | bicomd 523 | . . . 4 ⊢ (x = y → ([y / x]φ ↔ φ)) |
| 9 | sbhypf.2 | . . . 4 ⊢ (x = A → (φ ↔ ψ)) | |
| 10 | 8, 9 | sylan9bb 542 | . . 3 ⊢ ((x = y ⋀ x = A) → ([y / x]φ ↔ ψ)) |
| 11 | 6, 10 | 19.23ai 1066 | . 2 ⊢ (∃x(x = y ⋀ x = A) → ([y / x]φ ↔ ψ)) |
| 12 | 3, 11 | sylbir 201 | 1 ⊢ (y = A → ([y / x]φ ↔ ψ)) |
| Colors of variables: wff set class |
| Syntax hints: → wi 3 ↔ wb 146 ⋀ wa 223 ∀wal 956 = wceq 958 ∃wex 982 [wsbc 1172 |
| This theorem is referenced by: ac6sf 4770 |
| This theorem was proved from axioms: ax-1 4 ax-2 5 ax-3 6 ax-mp 7 ax-7 964 ax-gen 965 ax-10 968 ax-12 970 ax-17 973 ax-4 975 ax-5o 977 ax-6o 980 ax-9o 1125 ax-10o 1142 ax-16 1212 ax-11o 1220 ax-ext 1462 |
| This theorem depends on definitions: df-bi 147 df-an 225 df-ex 983 df-sb 1174 df-clab 1467 df-cleq 1472 df-clel 1475 df-v 1815 |