Proof of Theorem sssn
| Step | Hyp | Ref
| Expression |
| 1 | | ssel 2066 |
. . . . . . . . . . 11
⊢ (A ⊆ {B} → (x
∈ A
→ x ∈ {B})) |
| 2 | | elsni 2436 |
. . . . . . . . . . 11
⊢ (x ∈ {B} → x =
B) |
| 3 | 1, 2 | syl6 22 |
. . . . . . . . . 10
⊢ (A ⊆ {B} → (x
∈ A
→ x = B)) |
| 4 | | eleq1 1537 |
. . . . . . . . . 10
⊢ (x = B →
(x ∈
A ↔ B ∈ A)) |
| 5 | 3, 4 | syl6 22 |
. . . . . . . . 9
⊢ (A ⊆ {B} → (x
∈ A
→ (x ∈ A ↔
B ∈
A))) |
| 6 | 5 | ibd 596 |
. . . . . . . 8
⊢ (A ⊆ {B} → (x
∈ A
→ B ∈ A)) |
| 7 | 6 | 19.23adv 1216 |
. . . . . . 7
⊢ (A ⊆ {B} → (∃x x ∈ A → B ∈ A)) |
| 8 | | n0 2293 |
. . . . . . 7
⊢ (¬ A = ∅ ↔
∃x
x ∈
A) |
| 9 | 7, 8 | syl5ib 206 |
. . . . . 6
⊢ (A ⊆ {B} → (¬ A = ∅ →
B ∈
A)) |
| 10 | | snssi 2470 |
. . . . . 6
⊢ (B ∈ A → {B}
⊆ A) |
| 11 | 9, 10 | syl6 22 |
. . . . 5
⊢ (A ⊆ {B} → (¬ A = ∅ →
{B} ⊆
A)) |
| 12 | 11 | anc2li 302 |
. . . 4
⊢ (A ⊆ {B} → (¬ A = ∅ →
(A ⊆
{B} ⋀
{B} ⊆
A))) |
| 13 | | eqss 2080 |
. . . 4
⊢ (A = {B} ↔
(A ⊆
{B} ⋀
{B} ⊆
A)) |
| 14 | 12, 13 | syl6ibr 213 |
. . 3
⊢ (A ⊆ {B} → (¬ A = ∅ →
A = {B})) |
| 15 | 14 | orrd 233 |
. 2
⊢ (A ⊆ {B} → (A =
∅ ⋁
A = {B})) |
| 16 | | 0ss 2305 |
. . . 4
⊢ ∅ ⊆ {B} |
| 17 | | sseq1 2085 |
. . . 4
⊢ (A = ∅ →
(A ⊆
{B} ↔ ∅ ⊆ {B})) |
| 18 | 16, 17 | mpbiri 194 |
. . 3
⊢ (A = ∅ →
A ⊆
{B}) |
| 19 | | eqimss 2112 |
. . 3
⊢ (A = {B} →
A ⊆
{B}) |
| 20 | 18, 19 | jaoi 341 |
. 2
⊢ ((A = ∅ ⋁ A =
{B}) → A ⊆ {B}) |
| 21 | 15, 20 | impbi 157 |
1
⊢ (A ⊆ {B} ↔ (A =
∅ ⋁
A = {B})) |