Proof of Theorem undom
| Step | Hyp | Ref
| Expression |
| 1 | | endomtr 4426 |
. . . . . . . . . . 11
⊢ (((A ∪ C)
≈ (x ∪ y) ⋀ (x ∪ y) ≼ (B ∪
D)) → (A ∪ C) ≼ (B ∪
D)) |
| 2 | | unen 4440 |
. . . . . . . . . . . . . . 15
⊢ (((A ≈ x
⋀ (C
∖ A)
≈ y) ⋀ ((A ∩
(C ∖
A)) = ∅
⋀ (x
∩ y) = ∅)) → (A
∪ (C ∖ A)) ≈
(x ∪ y)) |
| 3 | | undif2 2345 |
. . . . . . . . . . . . . . 15
⊢ (A ∪ (C ∖ A)) =
(A ∪ C) |
| 4 | 2, 3 | syl5eqbrr 2654 |
. . . . . . . . . . . . . 14
⊢ (((A ≈ x
⋀ (C
∖ A)
≈ y) ⋀ ((A ∩
(C ∖
A)) = ∅
⋀ (x
∩ y) = ∅)) → (A
∪ C) ≈ (x ∪ y)) |
| 5 | | sseq2 2086 |
. . . . . . . . . . . . . . . . . 18
⊢ ((B ∩ D) =
∅ → ((x ∩ y) ⊆ (B ∩
D) ↔ (x ∩ y) ⊆ ∅)) |
| 6 | | ss0b 2306 |
. . . . . . . . . . . . . . . . . 18
⊢ ((x ∩ y) ⊆ ∅ ↔
(x ∩ y) = ∅) |
| 7 | 5, 6 | syl6bb 538 |
. . . . . . . . . . . . . . . . 17
⊢ ((B ∩ D) =
∅ → ((x ∩ y) ⊆ (B ∩
D) ↔ (x ∩ y) =
∅)) |
| 8 | | ss2in 2239 |
. . . . . . . . . . . . . . . . 17
⊢ ((x ⊆ B ⋀ y ⊆ D) → (x
∩ y) ⊆ (B ∩
D)) |
| 9 | 7, 8 | syl5bi 208 |
. . . . . . . . . . . . . . . 16
⊢ ((B ∩ D) =
∅ → ((x ⊆ B ⋀ y ⊆ D) → (x
∩ y) = ∅)) |
| 10 | 9 | imp 350 |
. . . . . . . . . . . . . . 15
⊢ (((B ∩ D) =
∅ ⋀
(x ⊆
B ⋀
y ⊆
D)) → (x ∩ y) =
∅) |
| 11 | | difdisj 2341 |
. . . . . . . . . . . . . . 15
⊢ (A ∩ (C ∖ A)) = ∅ |
| 12 | 10, 11 | jctil 292 |
. . . . . . . . . . . . . 14
⊢ (((B ∩ D) =
∅ ⋀
(x ⊆
B ⋀
y ⊆
D)) → ((A ∩ (C ∖ A)) = ∅ ⋀ (x ∩ y) =
∅)) |
| 13 | 4, 12 | sylan2 453 |
. . . . . . . . . . . . 13
⊢ (((A ≈ x
⋀ (C
∖ A)
≈ y) ⋀ ((B ∩
D) = ∅
⋀ (x
⊆ B
⋀ y
⊆ D)))
→ (A ∪ C) ≈ (x
∪ y)) |
| 14 | 13 | anassrs 443 |
. . . . . . . . . . . 12
⊢ ((((A ≈ x
⋀ (C
∖ A)
≈ y) ⋀ (B ∩
D) = ∅)
⋀ (x
⊆ B
⋀ y
⊆ D))
→ (A ∪ C) ≈ (x
∪ y)) |
| 15 | 14 | an1rs 491 |
. . . . . . . . . . 11
⊢ ((((A ≈ x
⋀ (C
∖ A)
≈ y) ⋀ (x ⊆ B ⋀ y ⊆ D)) ⋀ (B ∩
D) = ∅)
→ (A ∪ C) ≈ (x
∪ y)) |
| 16 | | unss12 2205 |
. . . . . . . . . . . . 13
⊢ ((x ⊆ B ⋀ y ⊆ D) → (x
∪ y) ⊆ (B ∪
D)) |
| 17 | | undom.1 |
. . . . . . . . . . . . . . 15
⊢ B ∈
V |
| 18 | | undom.3 |
. . . . . . . . . . . . . . 15
⊢ D ∈
V |
| 19 | 17, 18 | unex 2878 |
. . . . . . . . . . . . . 14
⊢ (B ∪ D) ∈ V |
| 20 | | ssdom2g 4415 |
. . . . . . . . . . . . . 14
⊢ ((B ∪ D) ∈ V → ((x ∪ y) ⊆ (B ∪
D) → (x ∪ y) ≼ (B ∪
D))) |
| 21 | 19, 20 | ax-mp 7 |
. . . . . . . . . . . . 13
⊢ ((x ∪ y) ⊆ (B ∪
D) → (x ∪ y) ≼ (B ∪
D)) |
| 22 | 16, 21 | syl 10 |
. . . . . . . . . . . 12
⊢ ((x ⊆ B ⋀ y ⊆ D) → (x
∪ y) ≼ (B ∪
D)) |
| 23 | 22 | ad2antlr 407 |
. . . . . . . . . . 11
⊢ ((((A ≈ x
⋀ (C
∖ A)
≈ y) ⋀ (x ⊆ B ⋀ y ⊆ D)) ⋀ (B ∩
D) = ∅)
→ (x ∪ y) ≼ (B ∪ D)) |
| 24 | 1, 15, 23 | sylanc 473 |
. . . . . . . . . 10
⊢ ((((A ≈ x
⋀ (C
∖ A)
≈ y) ⋀ (x ⊆ B ⋀ y ⊆ D)) ⋀ (B ∩
D) = ∅)
→ (A ∪ C) ≼ (B ∪ D)) |
| 25 | 24 | ex 373 |
. . . . . . . . 9
⊢ (((A ≈ x
⋀ (C
∖ A)
≈ y) ⋀ (x ⊆ B ⋀ y ⊆ D)) →
((B ∩ D) = ∅ →
(A ∪ C) ≼ (B ∪ D))) |
| 26 | 25 | an4s 510 |
. . . . . . . 8
⊢ (((A ≈ x
⋀ x
⊆ B)
⋀ ((C
∖ A)
≈ y ⋀ y ⊆ D)) →
((B ∩ D) = ∅ →
(A ∪ C) ≼ (B ∪ D))) |
| 27 | 26 | ex 373 |
. . . . . . 7
⊢ ((A ≈ x
⋀ x
⊆ B)
→ (((C ∖ A) ≈
y ⋀
y ⊆
D) → ((B ∩ D) =
∅ → (A ∪ C) ≼ (B ∪
D)))) |
| 28 | 27 | 19.23aiv 1297 |
. . . . . 6
⊢ (∃x(A ≈ x
⋀ x
⊆ B)
→ (((C ∖ A) ≈
y ⋀
y ⊆
D) → ((B ∩ D) =
∅ → (A ∪ C) ≼ (B ∪
D)))) |
| 29 | 28 | 19.23adv 1216 |
. . . . 5
⊢ (∃x(A ≈ x
⋀ x
⊆ B)
→ (∃y((C ∖ A) ≈
y ⋀
y ⊆
D) → ((B ∩ D) =
∅ → (A ∪ C) ≼ (B ∪
D)))) |
| 30 | 29 | imp 350 |
. . . 4
⊢ ((∃x(A ≈ x
⋀ x
⊆ B)
⋀ ∃y((C ∖ A) ≈ y
⋀ y
⊆ D))
→ ((B ∩ D) = ∅ →
(A ∪ C) ≼ (B ∪ D))) |
| 31 | 17 | domen 4385 |
. . . 4
⊢ (A ≼ B ↔ ∃x(A ≈ x
⋀ x
⊆ B)) |
| 32 | 18 | domen 4385 |
. . . 4
⊢ ((C ∖ A) ≼ D ↔ ∃y((C ∖ A) ≈ y
⋀ y
⊆ D)) |
| 33 | 30, 31, 32 | syl2anb 457 |
. . 3
⊢ ((A ≼ B ⋀ (C ∖ A) ≼ D) → ((B
∩ D) = ∅ → (A
∪ C) ≼ (B ∪
D))) |
| 34 | | undom.2 |
. . . . 5
⊢ C ∈
V |
| 35 | | difss 2170 |
. . . . 5
⊢ (C ∖ A) ⊆ C |
| 36 | | ssdom2g 4415 |
. . . . 5
⊢ (C ∈ V
→ ((C ∖ A) ⊆ C →
(C ∖
A) ≼
C)) |
| 37 | 34, 35, 36 | mp2 43 |
. . . 4
⊢ (C ∖ A) ≼ C |
| 38 | | domtr 4421 |
. . . 4
⊢ (((C ∖ A) ≼ C ⋀ C ≼ D) → (C
∖ A)
≼ D) |
| 39 | 37, 38 | mpan 697 |
. . 3
⊢ (C ≼ D → (C
∖ A)
≼ D) |
| 40 | 33, 39 | sylan2 453 |
. 2
⊢ ((A ≼ B ⋀ C ≼ D) → ((B
∩ D) = ∅ → (A
∪ C) ≼ (B ∪
D))) |
| 41 | 40 | imp 350 |
1
⊢ (((A ≼ B ⋀ C ≼ D) ⋀ (B ∩ D) =
∅) → (A ∪ C) ≼ (B ∪
D)) |