Proof of Theorem unidif0
| Step | Hyp | Ref
| Expression |
| 1 | | uniun 2523 |
. . . 4
⊢ ∪((A ∖ {∅}) ∪
{∅}) = (∪(A ∖ {∅}) ∪
∪{∅}) |
| 2 | | undif1 2344 |
. . . . . 6
⊢ ((A ∖ {∅}) ∪ {∅})
= (A ∪ {∅}) |
| 3 | | uncom 2179 |
. . . . . 6
⊢ (A ∪ {∅}) =
({∅} ∪ A) |
| 4 | 2, 3 | eqtr2 1499 |
. . . . 5
⊢ ({∅} ∪ A) =
((A ∖
{∅}) ∪ {∅}) |
| 5 | 4 | unieqi 2515 |
. . . 4
⊢ ∪({∅} ∪ A) = ∪((A ∖ {∅}) ∪ {∅}) |
| 6 | | 0ex 2716 |
. . . . . . 7
⊢ ∅ ∈
V |
| 7 | 6 | unisn 2521 |
. . . . . 6
⊢ ∪{∅} = ∅ |
| 8 | 7 | uneq2i 2184 |
. . . . 5
⊢ (∪(A ∖ {∅}) ∪
∪{∅}) = (∪(A ∖ {∅}) ∪
∅) |
| 9 | | un0 2301 |
. . . . 5
⊢ (∪(A ∖ {∅}) ∪
∅) = ∪(A ∖ {∅}) |
| 10 | 8, 9 | eqtr2 1499 |
. . . 4
⊢ ∪(A ∖ {∅}) = (∪(A ∖ {∅}) ∪
∪{∅}) |
| 11 | 1, 5, 10 | 3eqtr4r 1509 |
. . 3
⊢ ∪(A ∖ {∅}) = ∪({∅} ∪ A) |
| 12 | | uniun 2523 |
. . 3
⊢ ∪({∅} ∪ A) = (∪{∅} ∪ ∪A) |
| 13 | 7 | uneq1i 2183 |
. . 3
⊢ (∪{∅} ∪ ∪A) = (∅ ∪ ∪A) |
| 14 | 11, 12, 13 | 3eqtr 1502 |
. 2
⊢ ∪(A ∖ {∅}) = (∅ ∪ ∪A) |
| 15 | | uncom 2179 |
. 2
⊢ (∅ ∪ ∪A) = (∪A ∪ ∅) |
| 16 | | un0 2301 |
. 2
⊢ (∪A ∪ ∅) = ∪A |
| 17 | 14, 15, 16 | 3eqtr 1502 |
1
⊢ ∪(A ∖ {∅}) = ∪A |