| Metamath Proof Explorer |
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Related theorems GIF version |
| Description: Two ways to express "exclusive or." |
| Ref | Expression |
|---|---|
| xor3 | ⊢ (¬ (φ ↔ ψ) ↔ (φ ↔ ¬ ψ)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | pm5.18 662 | . . 3 ⊢ ((φ ↔ ψ) ↔ ¬ (φ ↔ ¬ ψ)) | |
| 2 | 1 | con2bii 221 | . 2 ⊢ ((φ ↔ ¬ ψ) ↔ ¬ (φ ↔ ψ)) |
| 3 | 2 | bicomi 172 | 1 ⊢ (¬ (φ ↔ ψ) ↔ (φ ↔ ¬ ψ)) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 2 ↔ wb 146 |
| This theorem is referenced by: notzfaus 2746 nmogtmnf 8429 nmopgtmnf 9790 |
| This theorem was proved from axioms: ax-1 4 ax-2 5 ax-3 6 ax-mp 7 |
| This theorem depends on definitions: df-bi 147 df-or 224 df-an 225 |