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Theorem xp2cda 4940
Description: Two times a cardinal number. Exercise 4.56(g) of [Mendelson] p. 258.
Hypothesis
Ref Expression
cda0en.1 A V
Assertion
Ref Expression
xp2cda (A × 2o) = (A +c A)

Proof of Theorem xp2cda
StepHypRef Expression
1 xpundi 3231 . 2 (A × ({} ∪ {1o})) = ((A × {}) ∪ (A × {1o}))
2 df-pr 2417 . . . 4 {, {}} = ({} ∪ {{}})
3 df2o2 4147 . . . 4 2o = {, {}}
4 df1o2 4146 . . . . . 6 1o = {}
54sneqi 2422 . . . . 5 {1o} = {{}}
65uneq2i 2184 . . . 4 ({} ∪ {1o}) = ({} ∪ {{}})
72, 3, 63eqtr4 1508 . . 3 2o = ({} ∪ {1o})
8 xpeq2 3207 . . 3 (2o = ({} ∪ {1o}) → (A × 2o) = (A × ({} ∪ {1o})))
97, 8ax-mp 7 . 2 (A × 2o) = (A × ({} ∪ {1o}))
10 cda0en.1 . . 3 A V
1110, 10cdaval 4932 . 2 (A +c A) = ((A × {}) ∪ (A × {1o}))
121, 9, 113eqtr4 1508 1 (A × 2o) = (A +c A)
Colors of variables: wff set class
Syntax hints:   = wceq 958   wcel 960  Vcvv 1814   ∪ cun 2048  c0 2283  {csn 2413  {cpr 2414   × cxp 3174  (class class class)co 3969  1oc1o 4134  2oc2o 4135   +c ccda 4929
This theorem is referenced by:  infunabs 7566  infcdaabs 7567
This theorem was proved from axioms:  ax-1 4  ax-2 5  ax-3 6  ax-mp 7  ax-7 964  ax-gen 965  ax-8 966  ax-9 967  ax-10 968  ax-11 969  ax-12 970  ax-13 971  ax-14 972  ax-17 973  ax-4 975  ax-5o 977  ax-6o 980  ax-9o 1125  ax-10o 1142  ax-16 1212  ax-11o 1220  ax-ext 1462  ax-sep 2708  ax-pow 2748  ax-pr 2785  ax-un 2872
This theorem depends on definitions:  df-bi 147  df-or 224  df-an 225  df-3an 779  df-ex 983  df-sb 1174  df-eu 1384  df-mo 1385  df-clab 1467  df-cleq 1472  df-clel 1475  df-ne 1590  df-rex 1653  df-v 1815  df-sbc 1945  df-csb 2005  df-dif 2052  df-un 2053  df-in 2054  df-ss 2056  df-nul 2284  df-pw 2406  df-sn 2416  df-pr 2417  df-op 2420  df-uni 2508  df-br 2625  df-opab 2672  df-id 2841  df-suc 2960  df-xp 3190  df-rel 3191  df-cnv 3192  df-co 3193  df-dm 3194  df-rn 3195  df-res 3196  df-ima 3197  df-fun 3198  df-fv 3204  df-opr 3971  df-oprab 3972  df-1o 4139  df-2o 4140  df-cda 4930
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