Proof of Theorem xpundi
| Step | Hyp | Ref
| Expression |
| 1 | | elun 2176 |
. . . . . 6
⊢ (y ∈ (B ∪ C)
↔ (y ∈ B ⋁ y ∈ C)) |
| 2 | 1 | anbi2i 482 |
. . . . 5
⊢ ((x ∈ A ⋀ y ∈ (B ∪ C))
↔ (x ∈ A ⋀ (y ∈ B ⋁ y ∈ C))) |
| 3 | | andi 606 |
. . . . 5
⊢ ((x ∈ A ⋀ (y ∈ B ⋁ y ∈ C)) ↔ ((x
∈ A ⋀ y ∈ B) ⋁ (x ∈ A ⋀ y ∈ C))) |
| 4 | 2, 3 | bitr 173 |
. . . 4
⊢ ((x ∈ A ⋀ y ∈ (B ∪ C))
↔ ((x ∈ A ⋀ y ∈ B) ⋁ (x ∈ A ⋀ y ∈ C))) |
| 5 | 4 | opabbii 2676 |
. . 3
⊢ {〈x, y〉∣(x ∈ A ⋀ y ∈ (B ∪
C))} = {〈x, y〉∣((x ∈ A ⋀ y ∈ B) ⋁ (x ∈ A ⋀ y ∈ C))} |
| 6 | | unopab 2684 |
. . 3
⊢ ({〈x, y〉∣(x ∈ A ⋀ y ∈ B)} ∪
{〈x,
y〉∣(x ∈ A ⋀ y ∈ C)}) = {〈x, y〉∣((x ∈ A ⋀ y ∈ B) ⋁ (x ∈ A ⋀ y ∈ C))} |
| 7 | 5, 6 | eqtr4 1501 |
. 2
⊢ {〈x, y〉∣(x ∈ A ⋀ y ∈ (B ∪
C))} = ({〈x, y〉∣(x ∈ A ⋀ y ∈ B)} ∪
{〈x,
y〉∣(x ∈ A ⋀ y ∈ C)}) |
| 8 | | df-xp 3190 |
. 2
⊢ (A × (B
∪ C)) = {〈x, y〉∣(x ∈ A ⋀ y ∈ (B ∪
C))} |
| 9 | | df-xp 3190 |
. . 3
⊢ (A × B) =
{〈x,
y〉∣(x ∈ A ⋀ y ∈ B)} |
| 10 | | df-xp 3190 |
. . 3
⊢ (A × C) =
{〈x,
y〉∣(x ∈ A ⋀ y ∈ C)} |
| 11 | 9, 10 | uneq12i 2185 |
. 2
⊢ ((A × B)
∪ (A × C)) = ({〈x, y〉∣(x ∈ A ⋀ y ∈ B)} ∪ {〈x, y〉∣(x ∈ A ⋀ y ∈ C)}) |
| 12 | 7, 8, 11 | 3eqtr4 1508 |
1
⊢ (A × (B
∪ C)) = ((A × B)
∪ (A × C)) |