Proof of Theorem xpundir
| Step | Hyp | Ref
| Expression |
| 1 | | elun 2176 |
. . . . . 6
⊢ (x ∈ (A ∪ B)
↔ (x ∈ A ⋁ x ∈ B)) |
| 2 | 1 | anbi1i 483 |
. . . . 5
⊢ ((x ∈ (A ∪ B) ⋀ y ∈ C) ↔
((x ∈
A ⋁
x ∈
B) ⋀
y ∈
C)) |
| 3 | | andir 607 |
. . . . 5
⊢ (((x ∈ A ⋁ x ∈ B) ⋀ y ∈ C) ↔ ((x
∈ A ⋀ y ∈ C) ⋁ (x ∈ B ⋀ y ∈ C))) |
| 4 | 2, 3 | bitr 173 |
. . . 4
⊢ ((x ∈ (A ∪ B) ⋀ y ∈ C) ↔
((x ∈
A ⋀
y ∈
C) ⋁
(x ∈
B ⋀
y ∈
C))) |
| 5 | 4 | opabbii 2676 |
. . 3
⊢ {〈x, y〉∣(x ∈ (A ∪
B) ⋀
y ∈
C)} = {〈x, y〉∣((x ∈ A ⋀ y ∈ C) ⋁ (x ∈ B ⋀ y ∈ C))} |
| 6 | | unopab 2684 |
. . 3
⊢ ({〈x, y〉∣(x ∈ A ⋀ y ∈ C)} ∪
{〈x,
y〉∣(x ∈ B ⋀ y ∈ C)}) = {〈x, y〉∣((x ∈ A ⋀ y ∈ C) ⋁ (x ∈ B ⋀ y ∈ C))} |
| 7 | 5, 6 | eqtr4 1501 |
. 2
⊢ {〈x, y〉∣(x ∈ (A ∪
B) ⋀
y ∈
C)} = ({〈x, y〉∣(x ∈ A ⋀ y ∈ C)} ∪
{〈x,
y〉∣(x ∈ B ⋀ y ∈ C)}) |
| 8 | | df-xp 3190 |
. 2
⊢ ((A ∪ B)
× C) = {〈x, y〉∣(x ∈ (A ∪
B) ⋀
y ∈
C)} |
| 9 | | df-xp 3190 |
. . 3
⊢ (A × C) =
{〈x,
y〉∣(x ∈ A ⋀ y ∈ C)} |
| 10 | | df-xp 3190 |
. . 3
⊢ (B × C) =
{〈x,
y〉∣(x ∈ B ⋀ y ∈ C)} |
| 11 | 9, 10 | uneq12i 2185 |
. 2
⊢ ((A × C)
∪ (B × C)) = ({〈x, y〉∣(x ∈ A ⋀ y ∈ C)} ∪ {〈x, y〉∣(x ∈ B ⋀ y ∈ C)}) |
| 12 | 7, 8, 11 | 3eqtr4 1508 |
1
⊢ ((A ∪ B)
× C) = ((A × C)
∪ (B × C)) |