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Theorem List for New Foundations Explorer - 801-900   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremanandi 801 Distribution of conjunction over conjunction. (Contributed by NM, 14-Aug-1995.)
((φ (ψ χ)) ↔ ((φ ψ) (φ χ)))
 
Theoremanandir 802 Distribution of conjunction over conjunction. (Contributed by NM, 24-Aug-1995.)
(((φ ψ) χ) ↔ ((φ χ) (ψ χ)))
 
Theoremanandis 803 Inference that undistributes conjunction in the antecedent. (Contributed by NM, 7-Jun-2004.)
(((φ ψ) (φ χ)) → τ)       ((φ (ψ χ)) → τ)
 
Theoremanandirs 804 Inference that undistributes conjunction in the antecedent. (Contributed by NM, 7-Jun-2004.)
(((φ χ) (ψ χ)) → τ)       (((φ ψ) χ) → τ)
 
Theoremimpbida 805 Deduce an equivalence from two implications. (Contributed by NM, 17-Feb-2007.)
((φ ψ) → χ)    &   ((φ χ) → ψ)       (φ → (ψχ))
 
Theorempm3.48 806 Theorem *3.48 of [WhiteheadRussell] p. 114. (Contributed by NM, 28-Jan-1997.)
(((φψ) (χθ)) → ((φ χ) → (ψ θ)))
 
Theorempm3.45 807 Theorem *3.45 (Fact) of [WhiteheadRussell] p. 113. (Contributed by NM, 3-Jan-2005.)
((φψ) → ((φ χ) → (ψ χ)))
 
Theoremim2anan9 808 Deduction joining nested implications to form implication of conjunctions. (Contributed by NM, 29-Feb-1996.)
(φ → (ψχ))    &   (θ → (τη))       ((φ θ) → ((ψ τ) → (χ η)))
 
Theoremim2anan9r 809 Deduction joining nested implications to form implication of conjunctions. (Contributed by NM, 29-Feb-1996.)
(φ → (ψχ))    &   (θ → (τη))       ((θ φ) → ((ψ τ) → (χ η)))
 
Theoremanim12dan 810 Conjoin antecedents and consequents in a deduction. (Contributed by Mario Carneiro, 12-May-2014.)
((φ ψ) → χ)    &   ((φ θ) → τ)       ((φ (ψ θ)) → (χ τ))
 
Theoremorim12d 811 Disjoin antecedents and consequents in a deduction. (Contributed by NM, 10-May-1994.)
(φ → (ψχ))    &   (φ → (θτ))       (φ → ((ψ θ) → (χ τ)))
 
Theoremorim1d 812 Disjoin antecedents and consequents in a deduction. (Contributed by NM, 23-Apr-1995.)
(φ → (ψχ))       (φ → ((ψ θ) → (χ θ)))
 
Theoremorim2d 813 Disjoin antecedents and consequents in a deduction. (Contributed by NM, 23-Apr-1995.)
(φ → (ψχ))       (φ → ((θ ψ) → (θ χ)))
 
Theoremorim2 814 Axiom *1.6 (Sum) of [WhiteheadRussell] p. 97. (Contributed by NM, 3-Jan-2005.)
((ψχ) → ((φ ψ) → (φ χ)))
 
Theorempm2.38 815 Theorem *2.38 of [WhiteheadRussell] p. 105. (Contributed by NM, 6-Mar-2008.)
((ψχ) → ((ψ φ) → (χ φ)))
 
Theorempm2.36 816 Theorem *2.36 of [WhiteheadRussell] p. 105. (Contributed by NM, 6-Mar-2008.)
((ψχ) → ((φ ψ) → (χ φ)))
 
Theorempm2.37 817 Theorem *2.37 of [WhiteheadRussell] p. 105. (Contributed by NM, 6-Mar-2008.)
((ψχ) → ((ψ φ) → (φ χ)))
 
Theorempm2.73 818 Theorem *2.73 of [WhiteheadRussell] p. 108. (Contributed by NM, 3-Jan-2005.)
((φψ) → (((φ ψ) χ) → (ψ χ)))
 
Theorempm2.74 819 Theorem *2.74 of [WhiteheadRussell] p. 108. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Andrew Salmon, 7-May-2011.)
((ψφ) → (((φ ψ) χ) → (φ χ)))
 
Theoremorimdi 820 Disjunction distributes over implication. (Contributed by Wolf Lammen, 5-Jan-2013.)
((φ (ψχ)) ↔ ((φ ψ) → (φ χ)))
 
Theorempm2.76 821 Theorem *2.76 of [WhiteheadRussell] p. 108. (Contributed by NM, 3-Jan-2005.)
((φ (ψχ)) → ((φ ψ) → (φ χ)))
 
Theorempm2.75 822 Theorem *2.75 of [WhiteheadRussell] p. 108. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 4-Jan-2013.)
((φ ψ) → ((φ (ψχ)) → (φ χ)))
 
Theorempm2.8 823 Theorem *2.8 of [WhiteheadRussell] p. 108. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 5-Jan-2013.)
((φ ψ) → ((¬ ψ χ) → (φ χ)))
 
Theorempm2.81 824 Theorem *2.81 of [WhiteheadRussell] p. 108. (Contributed by NM, 3-Jan-2005.)
((ψ → (χθ)) → ((φ ψ) → ((φ χ) → (φ θ))))
 
Theorempm2.82 825 Theorem *2.82 of [WhiteheadRussell] p. 108. (Contributed by NM, 3-Jan-2005.)
(((φ ψ) χ) → (((φ ¬ χ) θ) → ((φ ψ) θ)))
 
Theorempm2.85 826 Theorem *2.85 of [WhiteheadRussell] p. 108. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 5-Jan-2013.)
(((φ ψ) → (φ χ)) → (φ (ψχ)))
 
Theorempm3.2ni 827 Infer negated disjunction of negated premises. (Contributed by NM, 4-Apr-1995.)
¬ φ    &    ¬ ψ        ¬ (φ ψ)
 
Theoremorabs 828 Absorption of redundant internal disjunct. Compare Theorem *4.45 of [WhiteheadRussell] p. 119. (Contributed by NM, 5-Aug-1993.) (Proof shortened by Wolf Lammen, 28-Feb-2014.)
(φ ↔ ((φ ψ) φ))
 
Theoremoranabs 829 Absorb a disjunct into a conjunct. (Contributed by Roy F. Longton, 23-Jun-2005.) (Proof shortened by Wolf Lammen, 10-Nov-2013.)
(((φ ¬ ψ) ψ) ↔ (φ ψ))
 
Theorempm5.1 830 Two propositions are equivalent if they are both true. Theorem *5.1 of [WhiteheadRussell] p. 123. (Contributed by NM, 21-May-1994.)
((φ ψ) → (φψ))
 
Theorempm5.21 831 Two propositions are equivalent if they are both false. Theorem *5.21 of [WhiteheadRussell] p. 124. (Contributed by NM, 21-May-1994.)
((¬ φ ¬ ψ) → (φψ))
 
Theorempm3.43 832 Theorem *3.43 (Comp) of [WhiteheadRussell] p. 113. (Contributed by NM, 3-Jan-2005.)
(((φψ) (φχ)) → (φ → (ψ χ)))
 
Theoremjcab 833 Distributive law for implication over conjunction. Compare Theorem *4.76 of [WhiteheadRussell] p. 121. (Contributed by NM, 3-Apr-1994.) (Proof shortened by Wolf Lammen, 27-Nov-2013.)
((φ → (ψ χ)) ↔ ((φψ) (φχ)))
 
Theoremordi 834 Distributive law for disjunction. Theorem *4.41 of [WhiteheadRussell] p. 119. (Contributed by NM, 5-Aug-1993.) (Proof shortened by Andrew Salmon, 7-May-2011.) (Proof shortened by Wolf Lammen, 28-Nov-2013.)
((φ (ψ χ)) ↔ ((φ ψ) (φ χ)))
 
Theoremordir 835 Distributive law for disjunction. (Contributed by NM, 12-Aug-1994.)
(((φ ψ) χ) ↔ ((φ χ) (ψ χ)))
 
Theorempm4.76 836 Theorem *4.76 of [WhiteheadRussell] p. 121. (Contributed by NM, 3-Jan-2005.)
(((φψ) (φχ)) ↔ (φ → (ψ χ)))
 
Theoremandi 837 Distributive law for conjunction. Theorem *4.4 of [WhiteheadRussell] p. 118. (Contributed by NM, 5-Aug-1993.) (Proof shortened by Wolf Lammen, 5-Jan-2013.)
((φ (ψ χ)) ↔ ((φ ψ) (φ χ)))
 
Theoremandir 838 Distributive law for conjunction. (Contributed by NM, 12-Aug-1994.)
(((φ ψ) χ) ↔ ((φ χ) (ψ χ)))
 
Theoremorddi 839 Double distributive law for disjunction. (Contributed by NM, 12-Aug-1994.)
(((φ ψ) (χ θ)) ↔ (((φ χ) (φ θ)) ((ψ χ) (ψ θ))))
 
Theoremanddi 840 Double distributive law for conjunction. (Contributed by NM, 12-Aug-1994.)
(((φ ψ) (χ θ)) ↔ (((φ χ) (φ θ)) ((ψ χ) (ψ θ))))
 
Theorempm4.39 841 Theorem *4.39 of [WhiteheadRussell] p. 118. (Contributed by NM, 3-Jan-2005.)
(((φχ) (ψθ)) → ((φ ψ) ↔ (χ θ)))
 
Theorempm4.38 842 Theorem *4.38 of [WhiteheadRussell] p. 118. (Contributed by NM, 3-Jan-2005.)
(((φχ) (ψθ)) → ((φ ψ) ↔ (χ θ)))
 
Theorembi2anan9 843 Deduction joining two equivalences to form equivalence of conjunctions. (Contributed by NM, 31-Jul-1995.)
(φ → (ψχ))    &   (θ → (τη))       ((φ θ) → ((ψ τ) ↔ (χ η)))
 
Theorembi2anan9r 844 Deduction joining two equivalences to form equivalence of conjunctions. (Contributed by NM, 19-Feb-1996.)
(φ → (ψχ))    &   (θ → (τη))       ((θ φ) → ((ψ τ) ↔ (χ η)))
 
Theorembi2bian9 845 Deduction joining two biconditionals with different antecedents. (Contributed by NM, 12-May-2004.)
(φ → (ψχ))    &   (θ → (τη))       ((φ θ) → ((ψτ) ↔ (χη)))
 
Theorempm4.72 846 Implication in terms of biconditional and disjunction. Theorem *4.72 of [WhiteheadRussell] p. 121. (Contributed by NM, 30-Aug-1993.) (Proof shortened by Wolf Lammen, 30-Jan-2013.)
((φψ) ↔ (ψ ↔ (φ ψ)))
 
Theoremimimorb 847 Simplify an implication between implications. (Contributed by Paul Chapman, 17-Nov-2012.) (Proof shortened by Wolf Lammen, 3-Apr-2013.)
(((ψχ) → (φχ)) ↔ (φ → (ψ χ)))
 
Theorempm5.33 848 Theorem *5.33 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.)
((φ (ψχ)) ↔ (φ ((φ ψ) → χ)))
 
Theorempm5.36 849 Theorem *5.36 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.)
((φ (φψ)) ↔ (ψ (φψ)))
 
Theorembianabs 850 Absorb a hypothesis into the second member of a biconditional. (Contributed by FL, 15-Feb-2007.)
(φ → (ψ ↔ (φ χ)))       (φ → (ψχ))
 
Theoremoibabs 851 Absorption of disjunction into equivalence. (Contributed by NM, 6-Aug-1995.) (Proof shortened by Wolf Lammen, 3-Nov-2013.)
(((φ ψ) → (φψ)) ↔ (φψ))
 
Theorempm3.24 852 Law of noncontradiction. Theorem *3.24 of [WhiteheadRussell] p. 111 (who call it the "law of contradiction"). (Contributed by NM, 16-Sep-1993.) (Proof shortened by Wolf Lammen, 24-Nov-2012.)
¬ (φ ¬ φ)
 
Theorempm2.26 853 Theorem *2.26 of [WhiteheadRussell] p. 104. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 23-Nov-2012.)
φ ((φψ) → ψ))
 
Theorempm5.11 854 Theorem *5.11 of [WhiteheadRussell] p. 123. (Contributed by NM, 3-Jan-2005.)
((φψ) φψ))
 
Theorempm5.12 855 Theorem *5.12 of [WhiteheadRussell] p. 123. (Contributed by NM, 3-Jan-2005.)
((φψ) (φ → ¬ ψ))
 
Theorempm5.14 856 Theorem *5.14 of [WhiteheadRussell] p. 123. (Contributed by NM, 3-Jan-2005.)
((φψ) (ψχ))
 
Theorempm5.13 857 Theorem *5.13 of [WhiteheadRussell] p. 123. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 14-Nov-2012.)
((φψ) (ψφ))
 
Theorempm5.17 858 Theorem *5.17 of [WhiteheadRussell] p. 124. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 3-Jan-2013.)
(((φ ψ) ¬ (φ ψ)) ↔ (φ ↔ ¬ ψ))
 
Theorempm5.15 859 Theorem *5.15 of [WhiteheadRussell] p. 124. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 15-Oct-2013.)
((φψ) (φ ↔ ¬ ψ))
 
Theorempm5.16 860 Theorem *5.16 of [WhiteheadRussell] p. 124. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 17-Oct-2013.)
¬ ((φψ) (φ ↔ ¬ ψ))
 
Theoremxor 861 Two ways to express "exclusive or." Theorem *5.22 of [WhiteheadRussell] p. 124. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 22-Jan-2013.)
(¬ (φψ) ↔ ((φ ¬ ψ) (ψ ¬ φ)))
 
Theoremnbi2 862 Two ways to express "exclusive or." (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 24-Jan-2013.)
(¬ (φψ) ↔ ((φ ψ) ¬ (φ ψ)))
 
Theoremdfbi3 863 An alternate definition of the biconditional. Theorem *5.23 of [WhiteheadRussell] p. 124. (Contributed by NM, 27-Jun-2002.) (Proof shortened by Wolf Lammen, 3-Nov-2013.)
((φψ) ↔ ((φ ψ) φ ¬ ψ)))
 
Theorempm5.24 864 Theorem *5.24 of [WhiteheadRussell] p. 124. (Contributed by NM, 3-Jan-2005.)
(¬ ((φ ψ) φ ¬ ψ)) ↔ ((φ ¬ ψ) (ψ ¬ φ)))
 
Theoremxordi 865 Conjunction distributes over exclusive-or, using ¬ (φψ) to express exclusive-or. This is one way to interpret the distributive law of multiplication over addition in modulo 2 arithmetic. (Contributed by NM, 3-Oct-2008.)
((φ ¬ (ψχ)) ↔ ¬ ((φ ψ) ↔ (φ χ)))
 
Theorembiort 866 A wff disjoined with truth is true. (Contributed by NM, 23-May-1999.)
(φ → (φ ↔ (φ ψ)))
 
Theorempm5.55 867 Theorem *5.55 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 20-Jan-2013.)
(((φ ψ) ↔ φ) ((φ ψ) ↔ ψ))
 
1.2.7  Miscellaneous theorems of propositional calculus
 
Theorempm5.21nd 868 Eliminate an antecedent implied by each side of a biconditional. (Contributed by NM, 20-Nov-2005.) (Proof shortened by Wolf Lammen, 4-Nov-2013.)
((φ ψ) → θ)    &   ((φ χ) → θ)    &   (θ → (ψχ))       (φ → (ψχ))
 
Theorempm5.35 869 Theorem *5.35 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.)
(((φψ) (φχ)) → (φ → (ψχ)))
 
Theorempm5.54 870 Theorem *5.54 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 7-Nov-2013.)
(((φ ψ) ↔ φ) ((φ ψ) ↔ ψ))
 
Theorembaib 871 Move conjunction outside of biconditional. (Contributed by NM, 13-May-1999.)
(φ ↔ (ψ χ))       (ψ → (φχ))
 
Theorembaibr 872 Move conjunction outside of biconditional. (Contributed by NM, 11-Jul-1994.)
(φ ↔ (ψ χ))       (ψ → (χφ))
 
Theoremrbaib 873 Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.)
(φ ↔ (ψ χ))       (χ → (φψ))
 
Theoremrbaibr 874 Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.)
(φ ↔ (ψ χ))       (χ → (ψφ))
 
Theorembaibd 875 Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.)
(φ → (ψ ↔ (χ θ)))       ((φ χ) → (ψθ))
 
Theoremrbaibd 876 Move conjunction outside of biconditional. (Contributed by Mario Carneiro, 11-Sep-2015.)
(φ → (ψ ↔ (χ θ)))       ((φ θ) → (ψχ))
 
Theorempm5.44 877 Theorem *5.44 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.)
((φψ) → ((φχ) ↔ (φ → (ψ χ))))
 
Theorempm5.6 878 Conjunction in antecedent versus disjunction in consequent. Theorem *5.6 of [WhiteheadRussell] p. 125. (Contributed by NM, 8-Jun-1994.)
(((φ ¬ ψ) → χ) ↔ (φ → (ψ χ)))
 
Theoremorcanai 879 Change disjunction in consequent to conjunction in antecedent. (Contributed by NM, 8-Jun-1994.)
(φ → (ψ χ))       ((φ ¬ ψ) → χ)
 
Theoremintnan 880 Introduction of conjunct inside of a contradiction. (Contributed by NM, 16-Sep-1993.)
¬ φ        ¬ (ψ φ)
 
Theoremintnanr 881 Introduction of conjunct inside of a contradiction. (Contributed by NM, 3-Apr-1995.)
¬ φ        ¬ (φ ψ)
 
Theoremintnand 882 Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.)
(φ → ¬ ψ)       (φ → ¬ (χ ψ))
 
Theoremintnanrd 883 Introduction of conjunct inside of a contradiction. (Contributed by NM, 10-Jul-2005.)
(φ → ¬ ψ)       (φ → ¬ (ψ χ))
 
Theoremmpbiran 884 Detach truth from conjunction in biconditional. (Contributed by NM, 27-Feb-1996.)
ψ    &   (φ ↔ (ψ χ))       (φχ)
 
Theoremmpbiran2 885 Detach truth from conjunction in biconditional. (Contributed by NM, 22-Feb-1996.)
χ    &   (φ ↔ (ψ χ))       (φψ)
 
Theoremmpbir2an 886 Detach a conjunction of truths in a biconditional. (Contributed by NM, 10-May-2005.)
ψ    &   χ    &   (φ ↔ (ψ χ))       φ
 
Theoremmpbi2and 887 Detach a conjunction of truths in a biconditional. (Contributed by NM, 6-Nov-2011.) (Proof shortened by Wolf Lammen, 24-Nov-2012.)
(φψ)    &   (φχ)    &   (φ → ((ψ χ) ↔ θ))       (φθ)
 
Theoremmpbir2and 888 Detach a conjunction of truths in a biconditional. (Contributed by NM, 6-Nov-2011.) (Proof shortened by Wolf Lammen, 24-Nov-2012.)
(φχ)    &   (φθ)    &   (φ → (ψ ↔ (χ θ)))       (φψ)
 
Theorempm5.62 889 Theorem *5.62 of [WhiteheadRussell] p. 125. (Contributed by Roy F. Longton, 21-Jun-2005.)
(((φ ψ) ¬ ψ) ↔ (φ ¬ ψ))
 
Theorempm5.63 890 Theorem *5.63 of [WhiteheadRussell] p. 125. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 25-Dec-2012.)
((φ ψ) ↔ (φ φ ψ)))
 
Theorembianfi 891 A wff conjoined with falsehood is false. (Contributed by NM, 5-Aug-1993.) (Proof shortened by Wolf Lammen, 26-Nov-2012.)
¬ φ       (φ ↔ (ψ φ))
 
Theorembianfd 892 A wff conjoined with falsehood is false. (Contributed by NM, 27-Mar-1995.) (Proof shortened by Wolf Lammen, 5-Nov-2013.)
(φ → ¬ ψ)       (φ → (ψ ↔ (ψ χ)))
 
Theorempm4.43 893 Theorem *4.43 of [WhiteheadRussell] p. 119. (Contributed by NM, 3-Jan-2005.) (Proof shortened by Wolf Lammen, 26-Nov-2012.)
(φ ↔ ((φ ψ) (φ ¬ ψ)))
 
Theorempm4.82 894 Theorem *4.82 of [WhiteheadRussell] p. 122. (Contributed by NM, 3-Jan-2005.)
(((φψ) (φ → ¬ ψ)) ↔ ¬ φ)
 
Theorempm4.83 895 Theorem *4.83 of [WhiteheadRussell] p. 122. (Contributed by NM, 3-Jan-2005.)
(((φψ) φψ)) ↔ ψ)
 
Theorempclem6 896 Negation inferred from embedded conjunct. (Contributed by NM, 20-Aug-1993.) (Proof shortened by Wolf Lammen, 25-Nov-2012.)
((φ ↔ (ψ ¬ φ)) → ¬ ψ)
 
Theorembiantr 897 A transitive law of equivalence. Compare Theorem *4.22 of [WhiteheadRussell] p. 117. (Contributed by NM, 18-Aug-1993.)
(((φψ) (χψ)) → (φχ))
 
Theoremorbidi 898 Disjunction distributes over the biconditional. An axiom of system DS in Vladimir Lifschitz, "On calculational proofs" (1998), http://citeseerx.ist.psu.edu/viewdoc/summary?doi=10.1.1.25.3384. (Contributed by NM, 8-Jan-2005.) (Proof shortened by Wolf Lammen, 4-Feb-2013.)
((φ (ψχ)) ↔ ((φ ψ) ↔ (φ χ)))
 
Theorembiluk 899 Lukasiewicz's shortest axiom for equivalential calculus. Storrs McCall, ed., Polish Logic 1920-1939 (Oxford, 1967), p. 96. (Contributed by NM, 10-Jan-2005.)
((φψ) ↔ ((χψ) ↔ (φχ)))
 
Theorempm5.7 900 Disjunction distributes over the biconditional. Theorem *5.7 of [WhiteheadRussell] p. 125. This theorem is similar to orbidi 898. (Contributed by Roy F. Longton, 21-Jun-2005.)
(((φ χ) ↔ (ψ χ)) ↔ (χ (φψ)))
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