Proof of Theorem comi1
| Step | Hyp | Ref
| Expression |
| 1 | | ancom 74 |
. . . . 5
(b ∩ a) = (a ∩
b) |
| 2 | 1 | ax-r5 38 |
. . . 4
((b ∩ a) ∪ (b
∩ a⊥ )) = ((a ∩ b) ∪
(b ∩ a⊥ )) |
| 3 | | ax-a2 31 |
. . . 4
((a ∩ b) ∪ (b
∩ a⊥ )) = ((b ∩ a⊥ ) ∪ (a ∩ b)) |
| 4 | 2, 3 | ax-r2 36 |
. . 3
((b ∩ a) ∪ (b
∩ a⊥ )) = ((b ∩ a⊥ ) ∪ (a ∩ b)) |
| 5 | | lear 161 |
. . . 4
(b ∩ a⊥ ) ≤ a⊥ |
| 6 | 5 | leror 152 |
. . 3
((b ∩ a⊥ ) ∪ (a ∩ b)) ≤
(a⊥ ∪ (a ∩ b)) |
| 7 | 4, 6 | bltr 138 |
. 2
((b ∩ a) ∪ (b
∩ a⊥ )) ≤ (a⊥ ∪ (a ∩ b)) |
| 8 | | comi1.1 |
. . . 4
a C b |
| 9 | 8 | comcom 453 |
. . 3
b C a |
| 10 | 9 | df-c2 133 |
. 2
b = ((b
∩ a) ∪ (b ∩ a⊥ )) |
| 11 | | df-i1 44 |
. 2
(a →1 b) = (a⊥ ∪ (a ∩ b)) |
| 12 | 7, 10, 11 | le3tr1 140 |
1
b ≤ (a →1 b) |