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Theorem nom35 324
Description: Part of Lemma 3.3(14) from "Non-Orthomodular Models..." paper.
Assertion
Ref Expression
nom35 ((ab) ≡ a) = (a1 b)

Proof of Theorem nom35
StepHypRef Expression
1 bicom 96 . 2 ((ab) ≡ a) = (a ≡ (ab))
2 nom25 318 . 2 (a ≡ (ab)) = (a1 b)
31, 2ax-r2 36 1 ((ab) ≡ a) = (a1 b)
Colors of variables: term
Syntax hints:   = wb 1   ≡ tb 5   ∩ wa 7   →1 wi1 12
This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-a3 32  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38
This theorem depends on definitions:  df-b 39  df-a 40  df-t 41  df-f 42  df-i1 44
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