Proof of Theorem nom43
| Step | Hyp | Ref
| Expression |
| 1 | | ancom 74 |
. . . . . 6
(b⊥ ∩ a⊥ ) = (a⊥ ∩ b⊥ ) |
| 2 | | anor3 90 |
. . . . . 6
(a⊥ ∩ b⊥ ) = (a ∪ b)⊥ |
| 3 | 1, 2 | ax-r2 36 |
. . . . 5
(b⊥ ∩ a⊥ ) = (a ∪ b)⊥ |
| 4 | 3 | ud4lem0a 262 |
. . . 4
(b⊥ →4
(b⊥ ∩ a⊥ )) = (b⊥ →4 (a ∪ b)⊥ ) |
| 5 | 4 | ax-r1 35 |
. . 3
(b⊥ →4
(a ∪ b)⊥ ) = (b⊥ →4 (b⊥ ∩ a⊥ )) |
| 6 | | nom14 311 |
. . 3
(b⊥ →4
(b⊥ ∩ a⊥ )) = (b⊥ →1 a⊥ ) |
| 7 | 5, 6 | ax-r2 36 |
. 2
(b⊥ →4
(a ∪ b)⊥ ) = (b⊥ →1 a⊥ ) |
| 8 | | i3i4 270 |
. 2
((a ∪ b) →3 b) = (b⊥ →4 (a ∪ b)⊥ ) |
| 9 | | i2i1 267 |
. 2
(a →2 b) = (b⊥ →1 a⊥ ) |
| 10 | 7, 8, 9 | 3tr1 63 |
1
((a ∪ b) →3 b) = (a
→2 b) |