Theorem wanass 204

Description: Associative law.

Assertion

Ref	Expression
wanass	(((a ∩ b) ∩ c) ≡ (a ∩ (b ∩ c))) = 1

Proof of Theorem wanass

Step	Hyp	Ref	Expression
1		anass 76	. 2 ((a ∩ b) ∩ c) = (a ∩ (b ∩ c))
2	1	bi1 118	1 (((a ∩ b) ∩ c) ≡ (a ∩ (b ∩ c))) = 1

Syntax hints:   = wb 1   ≡ tb 5   ∩ wa 7  1wt 8

This theorem was proved from axioms:  ax-a1 30  ax-a2 31  ax-a3 32  ax-a5 34  ax-r1 35  ax-r2 36  ax-r4 37  ax-r5 38

This theorem depends on definitions:  df-b 39  df-a 40  df-t 41  df-f 42

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