Proof of Theorem womaa
| Step | Hyp | Ref
| Expression |
| 1 | | leo 158 |
. . 3
a⊥ ≤ (a⊥ ∪ (a ∩ b)) |
| 2 | | lear 161 |
. . 3
(a ∩ (a⊥ ∪ (a ∩ b)))
≤ (a⊥ ∪ (a ∩ b)) |
| 3 | 1, 2 | lel2or 170 |
. 2
(a⊥ ∪ (a ∩ (a⊥ ∪ (a ∩ b))))
≤ (a⊥ ∪ (a ∩ b)) |
| 4 | | leo 158 |
. . 3
a⊥ ≤ (a⊥ ∪ (a ∩ (a⊥ ∪ (a ∩ b)))) |
| 5 | | lea 160 |
. . . . 5
(a ∩ b) ≤ a |
| 6 | | leor 159 |
. . . . 5
(a ∩ b) ≤ (a⊥ ∪ (a ∩ b)) |
| 7 | 5, 6 | ler2an 173 |
. . . 4
(a ∩ b) ≤ (a ∩
(a⊥ ∪ (a ∩ b))) |
| 8 | | leor 159 |
. . . 4
(a ∩ (a⊥ ∪ (a ∩ b)))
≤ (a⊥ ∪ (a ∩ (a⊥ ∪ (a ∩ b)))) |
| 9 | 7, 8 | letr 137 |
. . 3
(a ∩ b) ≤ (a⊥ ∪ (a ∩ (a⊥ ∪ (a ∩ b)))) |
| 10 | 4, 9 | lel2or 170 |
. 2
(a⊥ ∪ (a ∩ b)) ≤
(a⊥ ∪ (a ∩ (a⊥ ∪ (a ∩ b)))) |
| 11 | 3, 10 | lebi 145 |
1
(a⊥ ∪ (a ∩ (a⊥ ∪ (a ∩ b)))) =
(a⊥ ∪ (a ∩ b)) |